Answer:
4 cm
Step-by-step explanation:
Perimeter = 18cm
θ = 2.5 radian
s = rθ, s = Arc length
Perimeter of Sector, P = arc length, s + 2r
Perimeter = rθ + 2r
r = Radius
18cm = r(2.5) + 2r
18cm = 2.5r + 2r
18cm = 4.5r
r = 18 /4.5
r = 4
Given:
In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.
To find:
The measure of angle P.
Solution:
According to the Law of Cosines:

Using Law of Cosines in triangle OPQ, we get




On further simplification, we get




Therefore, the measure of angle P is 79 degrees.
(6x + 30)+(2x+6)= 180
8x +36= 180
8x= 144
X= 18
So 2x+6 = 42
And 6x+30 = 138
Answer:
FIRST PROBLEM:
Exact Form:
x = 25
/19
Decimal Form:
x = 1.31578947
Mixed Number Form:
x = 1 6
/19
SECOND PROBLEM
Exact Form:
x = −
9 + √
106
, −
9 −
√
106
Decimal Form: x = 1.29563014
, −
19.29563014
Step-by-step explanation:
We know that the slope formula is m = (y1 - y2)/(x1 - x2)
Your points are: (3, 7) and (4, -8)
In this case,
x1 = 3
x2 = 4
y1 = 7
y2 = -8
Now, just plug in the numbers:
m = (7 - -8)/(3-4)
m = 15/-1
m = -15
Your slope is -15.