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satela [25.4K]
3 years ago
8

The winner of a 100 mile race drove his car to victory at a rate of 120.1229 mph. What was his time to the nearest thousandth of

an hour)?
His time was hours.

(Round to the nearest thousandth.)
Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

t=1.201\ \text{hour}

Step-by-step explanation:

Given that,

Distance, d = 100 mile

Velocity of the winner, v = 120.1229 mph

We know that velocity of an object is equal to distance per unit time. Let t is the time. So,

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{120.1229}{100 }\\\\t=1.201229\ \text{hour}\\\\\text{Round to the nearest thousandth}\\\\t=1.201\ \text{hour}

Hence, 1.201 hour is taken by the winner.

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Consider the function f(x)= 2/5x-4
Gre4nikov [31]

Answer: a) \frac{5}{2}x+10=f^{-1}(x)=g(x)

Step-by-step explanation:

Since we have given that

f(x)=\frac{2}{5}x-4

a.) Find the inverse of f(x) and name it g(x).

Let f(x) = y

So, it becomes

y=\frac{2}{5}x-4

Switching x to y , we get

x=\frac{2}{5}y-4

5x=2y-20\\\\5x+20=2y\\\\\frac{5x+20}{2}=y\\\\\frac{5}{2}x+10=y\\\\\frac{5}{2}x+10=f^{-1}(x)=g(x)

b) . Use composition to show that f(x) and g(x) are inverses of each other.

\mathrm{For}\:f=\frac{2}{5}x-4\:\\\\\mathrm{substitute}\:x\:\mathrm{with}\:g\left(x\right)=\frac{5}{2}x+10\\\\=\frac{2}{5}\left(\frac{5}{2}x+10\right)-4\\\\=x

Similarly,

\mathrm{g\left(x\right)=\frac{5}{2}x+10,\:f\left(x\right)=\frac{2}{5}x-4,\:g\left(x\right)\circ \:f\left(x\right)}\\\\\mathrm{For}\:g=\frac{5}{2}x+10\:\mathrm{substitute}\:x\:\mathrm{with}\:f\left(x\right)=\frac{2}{5}x-4\\\\=\frac{5}{2}\left(\frac{2}{5}x-4\right)+10\\\\=x

so, both are inverses of each other.

c) Draw the graphs of f(x) and g(x) on the same coordinate plane.

As shown below in the graph , Since for inverse function we need an axis of symmetry i.e. y=x

And both f(x) and g(x) are symmetry to y=x.

∴ f(x) and g(x) are inverses of each other.


5 0
4 years ago
On one day, 4 chefs and 5 helpers earned $650.
Arlecino [84]
4c + 5h = 650 and

5c + 6h = 800 where c are chefs, h are helpers

Start by finding an expression for c

4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4

Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50

Take that 50 and substitute it into the expression we have for c to get a number value for c

C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100

Check your first equations, substituting $50 for the helpers and $100 for the chefs.

4 (100) + 5(50) =
400 + 250 = 650

5(100) + 6(50) =
500 + 300 = 800
6 0
3 years ago
What is 2x+18 factored
Darina [25.2K]

Answer:

2(x+9)

Step-by-step explanation:

2x+18

find the common number which can fit into 2x and 18

in this case the number is 2

so; 2(x+9)

7 0
2 years ago
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Tom was in elementary school from 1997 to 2002 how much time was that in years
Sindrei [870]
Tom was in elementary school for about 5 years 
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4 years ago
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Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
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