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Law Incorporation [45]
3 years ago
8

Please help!!! trying to finish early

Mathematics
1 answer:
Scrat [10]3 years ago
6 0
To solve this problem you must apply the proccedure shown below:

 The linear functions have the form y=mx+b

 where m is the slope and b is the y- intercept

 Therefore, you have:

 1) The slope -6/5 and b=(0,8) is:

 y=(6/5)x+8

 
2) You have 3x-2y=1. Then, you only have to clear y:

 y=(3/2)x-1/2
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Which list of ordered pairs is NOT a function? Mark only one oval. {(1, 1), (2, 3), (3, 4), (4,5)} ){(1, 1), (2, 2), (3, 3), (4,
Mrac [35]

Answer:

{(1, 1), (1, 3), (2, 3), (3,4)}​ is not a function.

Step-by-step explanation:

The lists are:

a) {(1, 1), (2, 3), (3, 4), (4,5)}

b) {(1, 1), (2, 2), (3, 3), (4,4)}

c) {(1, 1), (3, 1), (4,2), (5, 3) }

d) {(1, 1), (1, 3), (2, 3), (3,4)}​

Firs, let's define what is a function.

A function is a relationship that maps elements from a set (the domain, is the set of the inputs) into elements of another set (the range, the set of the outputs) such that each element of the domain can be mapped into only one element of the range.

Then the list where we have the same input mapped into two different outputs, will not be a function.

Where in a ordered pair (x, y)

x is the input, and y is the output.

In this case, the list that is not a function is:

d) {(1, 1), (1, 3), (2, 3), (3,4)}​

because we have the input x = 1, mapped into two different outputs.

5 0
3 years ago
WHATIS THE MEANING OF A TERMINATING DECIMAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
jok3333 [9.3K]
The <u>correct answer</u> is:

A decimal that ends.

Explanation:

"Terminating" means ending.  A terminating decimal is one that has a last digit; it does not continue infinitely (never-ending) and it does not repeat infinitely.  It has a single digit at its end.
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4 years ago
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postnew [5]

Answer:

Uhh maybe 20284646392

Step-by-step explanation:

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3 years ago
Perform the indicated matrix row operation and write the new matrix
Ne4ueva [31]
The given operation involves just swapping the two rows, so carrying out R_1\leftrightarrow R_2 on the matrix gives

\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]
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4 years ago
How do i get a better grade if i'm failing
stellarik [79]
Ask for extra credit.

4 0
3 years ago
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