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nevsk [136]
3 years ago
15

A bag contains 4 red marbles, 2 blue marbles, 1 purple marble, and 3 green marbles.If a single marble is pulled out of the bag,

how many outcomes are in the sample space?
Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer: 10

Step-by-step explanation:

4 different outcomes based on color or 10 based amount

faust18 [17]3 years ago
5 0

Answer:

4 different outcomes based on color or 10 based on amount.

Step-by-step explanation:

I don't think it is specific enough for a definite answer.

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Basketball all the way!

Step-by-step explanation:

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How to divide 453 by 8 in standard form
Leno4ka [110]

Answer:

56 5/8

Step-by-step explanation:

     453/8

8 0
3 years ago
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
Find the difference equation<br> Y= a / x +b
Art [367]

Answer:

y+a+x=b

Step-by-step explanation:

hope it's work ty make me brainless tyy

7 0
2 years ago
35 birds to 45 birds?
sleet_krkn [62]
35:45

7:9 is your ratio

hope this helps

If you want the amount difference, it is an increase by 10 birds

hope this helps
6 0
3 years ago
Read 2 more answers
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