Question

What is the equation of the line that is parallel to the given line and passes trough the point (2,3)?

Answer 1

Answer:

The answer is c

Step-by-step explanation:

Answer 2

Answer:

$y=\frac{-1}{2}x + 4$

Step-by-step explanation:

First we need to find the slope of the given line, the one that is passing trough the points (-4,0) and (4,-4).

For that, lets use the slope`s equation $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

m= (-4-0) / (4-(-4)) = -1/2

A line that is parallel to this one must have its same slope, so m2= -1/2

Now, lets find the 'y' axis intercept point using the point given: (2,3)

And the equation for lines: y=mx+b

By evaluating (2,3) in the above expression we have:

3=-1/2 * 2 +b

From here, we obtain that b=4

Hence, our line is y=-1/2 * x + 4