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daser333 [38]
3 years ago
6

2) The ages of Sylvana’s two daughters are consecutive even integers. Find their ages if the sum of their ages is 38. a. Create

an equation to represent the situation. ) b. Solve for the ages of the daughters
Mathematics
1 answer:
irinina [24]3 years ago
4 0
As for this problem, it is needed to come up with an equation to represent the situation.

In this case, the simplest one would be this:

x + y = 38

Let us establish that we need to solve for x first to get the y (no matter which you solve first, you get the second one by using the first one)
To do this, we substitute y with this equation:

x + 2 = y

Then, substitute y with the equation. It should look like this:

x + (x + 2) = 38

Now all you have to do is solve.

2x = 36
----------
     2

x = 18

Then get they value of y

x + 2 = y
18 +2 = y
20 = y

So the answer for the ages of the daughters would be 18 and 20.

NOTE:
you can also use the equation

x - 2 = y     instead of       x + 2 = y

This will give you a value of 20 for x instead of 18 and 18 for y instead of 20. Either way, 18 and 20 will be the answer.

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A guy wire to a tower makes a 71° angle with level ground. At a point 36 ft farther from the tower than the wire but on the same
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The length of the wire is 37.15 ft

<u>Explanation:</u>

The figure is attached for the reference.

tan (71) = \frac{y}{x}

tan (36) = \frac{y}{36+x}

So,

tan(36) (36 + x) = y

tan(71) = \frac{tan (36) (36 + x )}{x}

2.9 = \frac{0.73 (36 + x)}{x} \\\\2.9 x = 26.28 + 0.73x\\\\2.17x = 26.28\\\\x = 12.11 ft

Substituting x = 12.11 ft in equation 1:

tan (71) = \frac{y}{12.11} \\\\2.9 X 12.11 = y\\\\y = 35.119 ft

Length of the wire, z = \sqrt{x^2 + y^2}

So,

z = \sqrt{(12.11)^2 + (35.119)^2} \\\\z = \sqrt{146.6521 + 1233.3442} \\\\z = 37.15 ft

Therefore, the length of the wire is 37.15 ft

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