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icang [17]
3 years ago
9

What is 3x+4(2-7x) what is the answer

Mathematics
1 answer:
Reil [10]3 years ago
3 0

Question -


What is 3x+4(2-7x) what is the answer


Answer:


= −25x+8


Hope i helped have a wonderful day..can i get a Brainliest please and thank you...

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Identify the leading term and leading coefficient of the polynomial expression. −4x6+9x2−9x5−3 Leading Term: Answer Leading Coef
LenKa [72]

Answer:

yay

Step-by-step explanation:

na

8 0
3 years ago
The expression 1.08s + 1.02b1.08s+1.02b predicts the end-of-year value of a financial portfolio where ss is the value of stocks
Marysya12 [62]

Answer:

$22350 is the predicted value of portfolio.

Step-by-step explanation:

The given expression is 1.08s + 1.02b1.08s + 1.02b which predicts the end of year value of a financial portfolio.Here s = value of stocks and b = value of bonds.

Now we have to calculate the value of a portfolio with s = $200 and b = $100

So we will put the values of s and b in the given expression to calculate the value portfolio.

1.08×200 +1.02×(100)×1.08×(200)+ 1.02×(100) = 216 + 22032 + 102

= $22350

The predicted end to end year value of portfolio is = $22350

3 0
3 years ago
Solve the triangle given that a=19 b=16, c=11.
kirill [66]

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle (a, b, c), but all angles are unknown (A, B, C). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that a = 19, b = 16 and c = 11, then the missing angles are, respectively:

Angle A

a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A (1)

A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)

A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right]

A \approx 87.395^{\circ}

Angle B

b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B (2)

B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)

B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right]

B\approx 57.271^{\circ}

Angle C

C = 180^{\circ}-A-B

C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}

C = 35.334^{\circ}

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

8 0
3 years ago
John and Annie have two distinguishable ponds. Initially, each of the ponds contains four ducks and five geese. John first picks
Sladkaya [172]

Answer: 4/9

Step-by-step explanation:

The probability that annie picks a duck Pt= the probability of picking a duck without accounting for the added one (Po)+ probability of picking the added bird and it's a duck(Pi)

Pt = Po+Pi

Since the total number of birds in the right pond is 10 after the addition of one by john

Po= 4/10

Pi= the of john adding a duck × the probability of annie picking the added bird

Pi= 4/9 × 1/10

Pi = 4/90

Pt= 4/10 + 4/90

Pt = (36+4)/90

Pt=40/90

Pt= 4/9

(This implies that the probability of picking a duck remain the same even after the addition of one bird from the left ponds because they both have equal proportions of duck and geese i.e the initial number of duck and geese in both right and left ponds are 4 and 5 respectively)

Thanks.

4 0
3 years ago
A box with a square and a closed top must have a volume of 125 cubic inches. Find the dimensions of the box that minimize the am
attashe74 [19]
If a box has a square base its volume will be:

V=hb^2  where h is the height...

h=V/b^2  we are told that V=125 so

h=125/b^2  now for the surface area, which consists of the two bases for a total of 2b^2.  It will also have four sides with a total area of 4(bh)=4bh so

A=2b^2+4bh, using h found above in this gives us:

A=2b^2+4b(V/b^2)

A=2b^2+4V/b

A=(2b^3+4V)/b, then taking the derivatives we can find the velocity of the area function.

dA/db=(6b^3-2b^3-4V)/b^2

dA/db=(4b^3-4V)/b^2

dA/db=0 when 4b^3-4V=0

b^3=V

b=V^(1/3), since V=125

b=5in, and since h=V/b^2

h=125/25=5in

So the dimensions that will minimize the amount of material used to enclose a volume of 125in^2 is a 5in cube.

h=b=5in
8 0
3 years ago
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