Andre and Morgan are both headed to Florida for vacation. Andre will drive 70 miles per hour. Morgan will drive 55 miles per hou
r but will leave 3 hours earlier than Andre. How many hours will Morgan have been driving before Andre catches up with her?
1 answer:
Answer:
14hours
Step-by-step explanation:
Since Andre and Morgan are both heading to the same location i.e Florida, they will have the same distance.
Distance = Speed × Time
For Morgan:
His speed = 55mi/hr
Let his time = x
Distance covered by Morgan = 55x
For Andre
His speed = 70mi/hr
Time = x-3 (since morgan leaves 3 hours earlier than Andre)
Distance covered = 70× (x-3) = 70(x-3)miles
Since they are driving towards the same location;
55x = 70(x-3)
55x = 70x-210
55x-70x = -210
-15x = -210
x = 210/15
x = 14
Hence Morgan will have been driving 14hours before Andre catch up
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