Question

Andre and Morgan are both headed to Florida for vacation. Andre will drive 70 miles per hour. Morgan will drive 55 miles per hour but will leave 3 hours earlier than Andre. How many hours will Morgan have been driving before Andre catches up with her?

Answer 1

Answer:

14hours

Step-by-step explanation:

Since Andre and Morgan are both heading to the same location i.e Florida, they will have the same distance.

Distance = Speed × Time

For Morgan:

His speed = 55mi/hr

Let his time = x

Distance covered by Morgan = 55x

For Andre

His speed = 70mi/hr

Time = x-3 (since morgan leaves 3 hours earlier than Andre)

Distance covered = 70× (x-3) = 70(x-3)miles

Since they are driving towards the same location;

55x = 70(x-3)

55x = 70x-210

55x-70x = -210

-15x = -210

x = 210/15

x = 14

Hence Morgan will have been driving 14hours before Andre catch up