Fit a quadratic function to these three points: (−2, 8), (0, −4), and (4, 68) y = −2x2 + 2x − 4 y = 4x2 + 2x − 4 y = −2x2 − 2x −

Question

deff fn [24]

3 years ago

11

Fit a quadratic function to these three points: (−2, 8), (0, −4), and (4, 68) y = −2x2 + 2x − 4 y = 4x2 + 2x − 4 y = −2x2 − 2x −

4 y = −4x2 − 2x − 4

Mathematics

1 answer:

vovangra [49] · Answer 1 · 2022-05-22T12:50:32+03:00

Answer:

y = 4x² + 2x − 4

Step-by-step explanation:

The y-values go down and up again, so the parabola opens upward. That means the x² coefficient must be positive. All answer choices are eliminated except one.

y = 4x² +2x -4

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There are other ways to get the answer. One of them is to use the quadratic regression function of a spreadsheet or graphing calculator. The one attached shows the points are matched by the equation ...

y = 4x² +2x -4 . . . . . as above