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andrey2020 [161]
3 years ago
6

Which segment is the line of reflection used in the following transformation?

Mathematics
1 answer:
never [62]3 years ago
3 0

Im sorry I know this is annoying but did you ever get an explanation on an answer?

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Seamus plays outside for five and five sixths hours every week. He has already played outside for four and three sixths hours. H
Ira Lisetskai [31]
I think it’s C because I did have this question but I’m not sure
5 0
3 years ago
Which of the following are not congruence theorems for right triangles? Check all that apply.
Lera25 [3.4K]

Answer:

c) HH E)AA

Step-by-step explanation:

Two right angles can be proved congruent by LA,LL,HA,HL properties.

HH and AA are not congruence property.

Two triangles can be proved similar by AA property. All congruent triangles are similar but all similar triangles are not similar.Hence right triangles can not be proved congruent by AA property.

Among the options given Option C and E are not congruence property.

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME IM STUCK ON A,B,C PLEASE HELP
navik [9.2K]

Answer:

1. Rotation

2. Reflection

3. Translation

Explanation:

1. Rotate figure A to the right it would match figure B

2. Imagine folding figure A down it would match figure B

3. Move figure A down and right and it would match figure B

4 0
3 years ago
Read 2 more answers
If the exterior angle of the bases is 140° in the measure of the angle of each base is wet and the measure of the vertex is what
seraphim [82]
Guevedvdidhdvdrvrjrbrirvrirvrutvbtirvtirirrorbr
7 0
3 years ago
Check answer please
Cerrena [4.2K]
The fourth or the D) Option is correct.

To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.

Multiply the scalar quantity with each element with respect to its row and column positioning that is,

Row × Column. So;

(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.

To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.

\mathcal{A = \begin{bmatrix}1 & 0 & 3 \\ 2 & -1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad 7A = 7 \times \begin{bmatrix}1 & 0 & 3 \\ 2 & - 1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad \begin{bmatrix}7 \times 1 & 7 \times 0 & 7 \times 3 \\ 7 \times 2 & 7 \times -1 & 7 \times 2 \\ 7 \times 0 & 7 \times 2 & 7 \times 1 \\ \end{bmatrix}}

\therefore \quad \begin{\bmatrix}7 & 14 & 0 \\ 0 & -7 & 14 \\ 21 & 14 & 7 \end{bmatrix}

Hope it helps.
5 0
3 years ago
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