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STatiana [176]
4 years ago
9

If f'(x) = ln (x-2), then the graph of y=f(x) is decreasing if and only if

Mathematics
1 answer:
oksano4ka [1.4K]4 years ago
7 0
This answer would be D. x>1
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Find the missing length indicated..
egoroff_w [7]

Answer:

I think it is 20 but I'm not sure. Sorry if you get it wrong.

Step-by-step explanation:

It's definatly not 4 or 7 because those lengths are too short to be where the question mark is. And 45 is too big for the missing length side.

Thx.

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3 years ago
Need help finding the median, mode , and mean 2,6,3,3,4,3,5,2,6,2
grigory [225]
Mode: 2 and 3
Median: 3
Mean:4
5 0
3 years ago
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The moon has a diameter of approximately 2,200 miles. If the circumference of a circle can be found using the formula C = πd, wh
Stells [14]

Answer:

The circumference is 6908 miles.

Step-by-step explanation:

C=πd

C=π*2200

C=3.14*2200

C=6908

Option B is correct.

8 0
4 years ago
The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard
Lena [83]

Answer:

The probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621

Step-by-step explanation:

We are given that

Mean,\mu=50000

Standard deviation,\sigma=2000

We have to find the probability of randomly selecting one employee who earned less than or equal to $45,000.

P(x\leq 45000)=P(\frac{x-\mu}{\sigma}\leq \frac{45000-50000}{2000})

P(x\leq 45000)=P(Z\leq-\frac{5000}{2000})

P(x\leq 45000)=P(Z\leq -2.5)

P(x\leq 45000)=0.00621

Hence,  the probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621

6 0
3 years ago
Considere a função de oferta como sendo y= 5x - 1/2 e a função de demanda como sendo y= -7x + 47/2 , onde x é a quantidade e y é
swat32

A) Temos que igualar isso a 2,50, que é o valor de y, ou seja, o valor do preço. Façamos isso, então, na função de demanda.

y = -7x + \frac{47}{2}

Substituir.

2,50 = - 7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x  = - \frac{47}{2} + 2,50

A fração 47/2 corresponde a 23,5. É mais interessante para nós, nesse caso, utilizar o valor decimal.

-7x  = - 23,5 + 2,50

Somar logo.

-7x = -21

Podemos multiplicar por -1 para tirar os sinais negativos.

7x = 21

Passar o x dividindo

x = \frac{21}{7}

Dividir

\boxed{x = 3}

Para um preço de R$ 2,50, a quantidade demandada é de 3 unidades.



B) Basta igualar as duas formulinhas.

5x - \frac{1}{2} = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x + 7x = \frac{47}{2} + \frac{1}{2}

Somar tudo. Como as frações têm o mesmo denominador, <u>nada de </u><u>mmc</u>! Basta somar os numeradores.

12x = \frac{48}{2}

Podemos dividir lá, olha:

12x = 24

Passar o x dividindo

x = \frac{24}{12}

Dividir

\boxed{x = 2}

O ponto de equilíbrio é o valor 2.



C) Basta, então, igualar as fórmulas da oferta e da demanda a 10.

Fórmula da oferta

10 = 5x - \frac{1}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x = 10 - \frac{1}{2}

Se 1/2 = 0,5, dá pra resolver sem fazer mmc:

5x = 10 - 0,5

Subtrair

5x = 9,5

Passar dividindo

x = \frac{9,5}{5}

Dividir.

\boxed{x = 1,9}

Fórmula da demanda

10 = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x = \frac{47}{2} - 10

Divide 47/2, vai.

-7x = 23,5 - 10

Subtrair.

-7x = 13,5

Passar o 7 dividindo.

x = - \frac{13,5}{7}

Vamos dividir e transformar em decimal.

\boxed{x = -1,9285714285714285714285714285714}


Subtrair a oferta pela demanda.

x = 1,9 - (-1,9285714285714285714285714285714)

Subtrair.

\boxed{x = 3,8285714285714285714285714285714}

Arredondando, o preço será de R$ 3,83.

8 0
3 years ago
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