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2 years ago

Darci wants to buy a computer that

Mathematics

2 answers:

disa [49]2 years ago

6 0

Step-by-step explanation:

To find how many hours

you would do: the cost of computer/money earner per hour

so 1308/11=118.9 round it

so she needs to work 119 hours to earn enough money

So her money after 119 hours is

11*119 is $1,309

Hope this helps!!!!

Have a nice day :)

frutty [35]2 years ago

5 0

Answer:

119 hours

Step-by-step explanation:

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Evaluate. 68.14 + 0.0007

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Answer:

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Step-by-step explanation:

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2 years ago

James earns $13 an hour. John earns $4 an hour. If, after working for a whole number of hour, they both earned the same amount,

Sloan [31]

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2 years ago

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Help me I dunno know.

k0ka [10]

There is a rule:

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3 years ago

Write the inequality represented by the graph below

olchik [2.2K]

Answer:

y≥3x-1

Step-by-step explanation:

i did the thing

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2 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

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1 year ago