When a body is moving in circular path at a
distance r from its center its velocity at any
instant will be directed tangentially. This is
what we call tangential velocity. It is
calculated as follows:
Vt=r(w)
where w = 5 rev/s (2m rad / rev) = 31.42
rad/s
Vt = 0.24(31.42) = 7.5 m/s
The value of xy from the given equation is (y ²z²)(√x÷ z²)
<h3>How to solve equation?</h3>
x = y ²z²
make y the subject
y² = x ÷ z²
y = √x÷ z²
xy = x × y
xy = (y ²z²)(√x÷ z²)
Therefore, the value of xy from the given equation is (y ²z²)(√x÷ z²)
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Answer:
Gravity pull them on the ground
Explanation:
Answer:
Explanation:
Given
Required
Evaluate the sequence
The sequence shows an arithmetic progression and will be solved using the sum of n terms of an Arithmetic Sequence as follows:
But first, we need to determine the value of n as follows:
Where
So:
Open bracket
Collect Like Terms
Divide through by 2
So:
becomes
<em>Hence, the sum of the sequence is 62750</em>
