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3 years ago

X-6.6=15.7 A. 9.1 B. 22.3 C. 27.3 D. 32.3

Mathematics

2 answers:

QveST [7]3 years ago

7 0

Answer:

Step-by-step explanation:

A because 15.7 - 6.6= 9.1

Olin [163]3 years ago

7 0

Answer:

Your answer is B. :)

Step-by-step explanation:

22.3 - 6.6 = 15.7

Work check.

22.3

6.6

---------

15.7

(3 gets changed to 13, so it's 13-6 which equals 7. The 2 was changed to 1 to make the 13. So, it gets turned 11-6 which equals 5. The 2 was changed to 1 to make the 11, so you bring the 1 down. Then, just bring the decimal point down and you're done.)

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What is the value of x? 6 8 010 O 12

Morgarella [4.7K]

Answer:

Step-by-step explanation:

The sum of the internal angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

here n = 5, hence

sum = 180° × 3 = 540°

Each exterior angle plus interior angle = 180°

Subtract each exterior angle from 180 for corresponding interior angle.

180 - 59 = 121, 180 - 77 = 103, 180 - 66 = 114, 180 - 62 = 118

Sum the 4 interior angles and subtract from 540 for 5 th interior angle

5 th = 540° - (121 + 103 + 114 + 118)° = 540° - 456° = 84°

The 5 th interior angle and 12x sum to 180 ( same reason as above )

Hence

12x + 84 = 180 ( subtract 84 from both sides )

12x = 96 ( divide both sides by 12 )

x = 8

please mark me brainliest :)

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4 years ago

Read 2 more answers

Your patient weighs 15 kg and is scheduled for to have an abdominal exploratory. You are instructed to provide 0.9% sodium chlor

kumpel [21]

Answer:

$V_f=450ml/hr$

Step-by-step explanation:

From the question we are told that:

Mass $m=15kg$

Amount of NaCl IV $n=0.9\%$

Rate $R=30ml/kg/hr$

Generally the equation for fluid rate be for your IV pump is mathematically given by

$V_f=mR$

Since

Rate is

30ml/kg/hr at 1kg patient Weight

Therefore

$V_f=15*30$

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3 years ago

, find f^{-1}(x)f −1 (x)

Stolb23 [73]

Answer:

Multiply the numerator by the reciprocal of the denominator. Multiply x x by 1 1 . Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=1x f - 1 ( x ) = 1 x is the inverse of f(x)=1x f ( x ) = 1 x .

Step-by-step explanation:

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2 years ago

Two friends store 3 cereal bors equally. How many cored bors each person get? Show your work Write an equation & solution: E

maria [59]

Answer:

1 $\frac{1}{2}$

Step-by-step explanation:

There are a total of 2 friends, if they have 3 cereal bars and want to split it equally then we simply need to divide the number of cereal bars by the number of friends which would give us the number of cereal bars that each individual will get, which will be represented by x

x = 3 / 2

x = 1 $\frac{1}{2}$

Finally, we can see that each friend will get a total of 1 and a half of a cereal bar.

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3 years ago

An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 150 lb and

lisov135 [29]

Answer:

(a) 0.50928

(b) 0.857685.

Step-by-step explanation:

We are given that an engineer is going to redesign an ejection seat for an airplane. The new population of pilots has normally distributed weights with a mean of 155 lb and a standard deviation of 29.2 lb i.e.; $\mu$ = 160 lb and $\sigma$ = 27.5 lb

(A) We know that Z = $\frac{X - \mu}{\sigma}$ ~ N(0,1)

Let X = randomly selected pilot

If a pilot is randomly selected, the probability that his weight is between 150 lb and 201 lb = P(150 < X < 201)

P(150 < X < 201) = P(X < 201) - P(X <= 150)

P(X < 201) = P( $\frac{X - \mu}{\sigma}$ < $\frac{201 - 155}{29.2}$ ) = P(Z < 1.57) = 0.94179

P(X <= 150) = P( $\frac{X - \mu}{\sigma}$ < $\frac{150 - 155}{29.2}$ ) = P(Z < -0.17) = 1 - P(Z < 0.17) = 1 - 0.56749

= 0.43251

Therefore, P(150 < X < 201) = 0.94179 - 0.43251 = 0.50928 .

(B) We know that for sampling mean distribution;

Z = $\frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

If 39 different pilots are randomly selected, the probability that their mean weight is between 150 lb and 201 lb is given by P(150 < X bar < 210);

P(150 < X bar < 210) = P(X bar < 201) - P(X bar <= 150)

P(X bar < 201) = P( $\frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{201 - 155}{\frac{29.2}{\sqrt{39} } }$ ) = P(Z < 9.84) = 1 - P(Z >= 9.84)

= 0.999995

P(X bar <= 150) = P( $\frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{150 - 155}{\frac{29.2}{\sqrt{39} } }$ ) = P(Z < -1.07) = 1 - P(Z < 1.07)

= 1 - 0.85769 = 0.14231

Therefore, P(150 < X bar < 210) = 0.999995 - 0.14231 = 0.857685.

C) If the tolerance level is very high to accommodate an individual pilot then it should be appropriate ton consider the large sample i.e. Part B probability is more relevant in that case.

3 0

3 years ago