0.7 is 10 times as great as?

Nina [5.8K]

Answer:

$3500 he can take off his income as a capital loss this year.

Step-by-step explanation:

Capital loss:

1. It is the loss realized when any investment's value gets decreased.

2. quantitatively it is the difference of price at which the invest is bought and price at which the investment is sold.

3. The condition for capital loss is that , selling price of investment should be less that buying price of same investment.

_________________________________________

Given

No. of shares bought = 500

cost of 1 share = $10

cost of 500 share = 500 *$10 = $5000

Thus, buying price of invest = $5000

Now price of share drops to $3 per share

thus total price of share now = 500*$3 = $1500

Thus, he sold his investment at $1500

capital loss incurred by him = $5000 - $1500 = $3500 (Answer)

3 0

3 years ago

Read 2 more answers

A manufacturer of metal fasteners expects to ship an average of 1197.00 boxes of fasteners per day. A random sample of 24 days p

lana66690 [7]

Answer:

The p-value obtained is less than the significance level at which the test was performed, hence, we reject the null hypothesis, accept the alternative hypothesis & conclude that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Step-by-step explanation:

For hypothesis testing, we first clearly state our null and alternative hypothesis.

The null hypothesis is that there is no evidence showing that the average number of boxes shipped per day is different from 1197.00. That is, there is no significant difference between the number of boxes shipped per day and 1197.00

And the alternative hypothesis is that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Mathematically, the null hypothesis is

H₀: μ₀ = 1197.00

The alternative hypothesis is

Hₐ: μ₀ ≠ 1197.00

To do this test, we will use the t-distribution because no information on the population standard deviation is known

So, we compute the t-test statistic

t = (x - μ₀)/σₓ

x = sample mean = 1193.69 boxes per day

μ₀ = standard that we're comparing the sample mean with = 1197.00

σₓ = standard error of the sample mean

= (σ/√n)

where n = Sample size = 24 days

σ = standard deviation of the sample = 3.3166 boxes per day

σₓ = (3.3166/√24) = 0.677

t = (1193.69 - 1197) ÷ 0.677

t = -4.89

checking the tables for the p-value of this t-statistic

Degree of freedom = df = n - 1 = 24 - 1 = 23

Significance level = 0.05

p-value (for t = -4.89, at 0.05 significance level, with a two tailed condition) = 0.000061

The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 5% = 0.05

p-value = 0.000061

0.000061 < 0.05

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & conclude that there is evidence showing that the average number of boxes shipped per day is different from 1197.00

Hope this Helps!!!

6 0

3 years ago

At George Washington High School the ratio of graduating seniors that go on to college, as compared to those who do not, is 7 :

soldi70 [24.7K]

First you figure out that the ratio 7:4 is 1.75
Then you do this problem 28 divided by 1.75=16
And 28:16 is the same as 7:4
Now all you do is add 28+16=44

6 0

3 years ago

tossing a number cube numbered from 1 to 6 and getting an Evan number that is greater than of equal to 2

photoshop1234 [79]

Even numbers on die: 2,4,6
odd numbers on die: 1,3,5
3+3=6 -> 6 numbers in total
3/6 chance because there are 3 even numbers. This would round to 1/2, so 1/2 a chance the die will roll an even number.

5 0

3 years ago

An automobile manufacturer has discovered that 20% of all the transmissions it installed in a particular style of truck are defe

Hatshy [7]

Answer:

0.148 = 14.8% probability that they will need to order at least one more new transmission

Step-by-step explanation:

For each transmission, there are only two possible outcomes. Either it is defective after a year of use, or it is not. The probability of a transmission being defective is independent of any other transmission. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$