<h2>
Answer:</h2>
<h2>
Step-by-step explanation:</h2>
I've drawn a graph in order to a better understanding of this problem. We know that:
BC is perpendicular to AC
∠DBE = 2x - 1
∠CBE = 5x - 42
Let's call the intersection of line BC and AC the point P, so:
∠P=90°
And points B, P and C form the triangle ΔBPC. On the other hand, ∠CBE and ∠PCB are Alternate Interior Angles, so:
∠PCB = ∠CBE = 5x - 42
Moreover:
∠PBC = 2x - 1 - (5x - 42)
∠PBC = 2x - 1 - 5x + 42
∠PBC = -3x + 41
The internal angles of any triangle add up to 180°. Hence for ΔBPC:
90° + ∠PBC + ∠PCB = 180°
90° - 3x + 41 + 5x - 42 = 180°
2x + 89 = 180
2x = 91
x = 45.5°
Answer:
T
Step-by-step explanation:
<u>Answer:</u>
(4, 4)
<u>Step-by-step explanation:</u>
On the Cartesian plane, values on the x-axis increase to the right, and values on the y-axis increase as you go vertically upwards.
x-coordinate = 2
y-coordinate = 3
•Moving 2 units to the right adds 2 to the x-coordinate.
∴ new x-coordinate = 2 + 2 = 4
• Moving 1 unit up adds 1 to the y-coordinate.
∴ new y-coordinate = 3 + 1 = 4
∴ You will end up on the point (4, 4).