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earnstyle [38]
3 years ago
11

When working with scatterplots and the dots line up on a graph, but more in a curvy line, this would be an example of which mode

l?
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0
The best answer to this question is quadratic. The model that can be seen in a scatterplot wherein the dots line up on a graph in a curvy manner would be the quadratic model. 

Additional info: If the dots are forming a straight lne, it's linear. If it shoots up, then it's an exponential one.
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What is the approximate solution of this system of equations?
Effectus [21]
Hmm, I'd say it's the first option.
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Question 18.
DENIUS [597]

Answer: c

Step-by-step explanation:

sampling variability is the difference between the measured value of the random sample and the mean age of the population

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3 years ago
Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz
Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The <em>vertical</em> component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>horizontal</em> direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>vertical</em> direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11

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brainly.com/question/24629099

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2 years ago
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rusak2 [61]

Answer:

(4 ,26)

Step-by-step explanation:

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which the point with coordinates (4 , 26)

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3 years ago
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Use the distributive property to find the missing number.<br> __× (9 + 8) = (15 × 9) + (15 × 8)
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Answer:

The missing number is 15

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3 years ago
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