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4 years ago

Using the polynomials Q = 3 x2 + 5 x - 2, R = 2 - x2 , and S = 2 x + 5, perform the indicated operation.

Mathematics

1 answer:

marusya05 [52]4 years ago

4 0

Answer:

4x^2 + 3x - 9

Step-by-step explanation:

First, add together functions R(x) and S(x). Stack them vertically and combine like terms:

R(x) = 2 - x^2

S(x) = 2x + 5

------------------

(R+S)(x) = -x^2 + 2x + 7

Now subtract the above result from Q(x):

Q(x) - (R(x) + S(x)) = 3x^2 + 5x - 2 + x^2 - 2x - 7, or 4x^2 + 3x - 9

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Pls help, i'll give you a brainliest 4 answer <3

babymother [125]

Answer:

$x = 45 \ \& \ y = 5$

Step-by-step explanation:

The system of linear equations in two variables is ,

$\begin{cases} x = 9y \cdots (i)\\ x - 5y = 20\cdots (ii) \end{cases}$

We can easily solve out this Question using substitution method . For that , substituting x = 9y from equation (i) to equation (ii) , we have ,

$\implies x - 5y = 20 \\\\\implies 9y - 5y = 20 \\\\\implies 4y = 20 \\\\\implies y =\dfrac{20}{4}\\\\\implies\boxed{\boxed{ y = 5 }}$

Substituting this value in (i) ,

$\implies x = 9y \\\\\implies x = 9\times 5 \\\\\implies \boxed{\boxed{ x = 45 }}$

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Answer:

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Step-by-step explanation:

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4 years ago

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barxatty [35]

Equal to 1:

$3*\frac{1}{3}\ \ , \ \ 5*\frac{1}{5}\ \ , \ \6*\frac{1}{6}$

Less than 1:

$1*\frac{5}{6}$

Greater than 1:

$2 * \frac{3}{4} \ \ , \ \ \ 3 * \frac{2}{5}$

Step-by-step explanation:

We will solve each product one by one.

So,

$3*\frac{1}{3} = 1\\\\6*\frac{1}{6} = 1\\\\2 * \frac{3}{4} = \frac{3}{2}\\\\1*\frac{5}{6} = \frac{5}{6}\\\\3*\frac{2}{5} = \frac{6}{5}\\\\5*\frac{1}{5} = \frac{1}{5}$

As we have all the answers now.

If the denominator of a fraction is greater than ts numerator then the result is less than 1
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So,

Equal to 1:

$3*\frac{1}{3}\ \ , \ \ 5*\frac{1}{5}\ \ , \ \6*\frac{1}{6}$

Less than 1:

$1*\frac{5}{6}$

Greater than 1:

$2 * \frac{3}{4} \ \ , \ \ \ 3 * \frac{2}{5}$

Keywords: Fractions, decimals

Learn more about fractions at:

#LearnwithBrainly

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