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3 years ago

which set of three numbers could be the side lengths of a triangle A.5,5,14 B.3,3,2 C.3,3,8 D. 5,5,10

Mathematics

1 answer:

Ivanshal [37]3 years ago

4 0

Answer:

B. 3, 3, 2

Step-by-step explanation:

The triangle inequality requires the sum of the lengths of the two shortest sides exceed the length of the longest side. That is the case only for the lengths of selection B:

2 + 3 > 3

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Step-by-step explanation:

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Please help me with this problem

My name is Ann [436]

Answer:

$6A- 8B = \left[\begin{array}{ccc}56&50&-14\\-126&92&62\\-78&26&2\end{array}\right]$

Option A is correct.

Step-by-step explanation:

$A=\left[\begin{array}{ccc}-4&-1&-9\\-9&6&9\\-1&-1&3\end{array}\right] \\B=\left[\begin{array}{ccc}-10&-7&-5\\9&-7&-1\\9&-4&2\end{array}\right]$

We need to find 6A - 8B

Multiply matrix A with 6 and matrix B with 8 and then subtract 6A - 8B

$6A=\left[\begin{array}{ccc}-24&-6&-54\\-54&36&54\\-6&-6&18\end{array}\right] \\8B=\left[\begin{array}{ccc}-80&-56&-40\\72&-56&-8\\72&-32&16\end{array}\right]\\6A - 8B =\left[\begin{array}{ccc}-24-(-80)&-6-(-56)&-54-(-40)\\-54-(72)&36-(-56)&54-(-8)\\-6-(72)&-6-(-32)&18-(16)\end{array}\right] \\6A - 8B =\left[\begin{array}{ccc}-24+80&-6+56&-54+40\\-54-72&36+56&54+8\\-6-72&-6+32&18-16\end{array}\right] \\6A- 8B = \left[\begin{array}{ccc}56&50&-14\\-126&92&62\\-78&26&2\end{array}\right]$

So, $6A- 8B = \left[\begin{array}{ccc}56&50&-14\\-126&92&62\\-78&26&2\end{array}\right]$

Option A is correct.

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