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mixas84 [53]
3 years ago
12

How do you reduce 16/72

Mathematics
2 answers:
Usimov [2.4K]3 years ago
4 0

Answer:

2/9

Step-by-step explanation:

16/72 = (8×2)/ (8×9)=2/9

grandymaker [24]3 years ago
3 0

Answer: 2/9

Step-by-step explanation:

Divide it by 2 and keep going until you can't anymore.

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the difference of two numbers is eight the first number x is one less than twice the second number y write and solve a system of
jeka94
<h3>Answer:</h3>

The two numbers are 17 and 9.

<h3>Explanation:</h3>

<em>System of Equations</em>

Let x and y represent the first and second numbers, respectively.

... x - y = 8 . . . . . . . . . the difference of the two numbers is 8

... x = 2y - 1 . . . . . . . . .the first number is one less than twice the second

<em>Solution</em>

The second equation gives an expression for x that can be substituted into the first equation.

... (2y -1) -y = 8

... y -1 = 8 . . . . . . . collect terms

... y = 9 . . . . . . . . . add 1

... x = 2·9 -1 = 18 -1

... x = 17

The first number is 17; the second number is 9.

4 0
4 years ago
Simplify the ratio 24/36
yKpoI14uk [10]
You reduce 24/36. 12/18, 6/9, 2/3
8 0
3 years ago
Read 2 more answers
Write a number that is greater than 8.604 but less than 8.643
Aliun [14]
8.605
This number is bigger than 6.604 and it is smaller than 8.643
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6 0
4 years ago
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The astronauts from apollo 17 completed 3 space walks while on the moon for a total duration of 22 hour 4 minutes how many minut
Vadim26 [7]

Answer:

The duration of each of the three spacewalk is between 364 minutes and 480 minutes with a total duration of 1324 minutes

Step-by-step explanation:

A spacewalk also termed an EVA or extravehicular activity, is defined as the general activity of an astronaut outside of a vehicle in space

Spacewalks can last up to 5 to 8 hours

Here we have a word problem, and are required to find the number of minutes equivalent to 22 hour and 4 minutes

Number of minutes per hour = 60 minutes

Number of minutes in 22 hours = 60 × 22 = 1320 minutes

Total number of minutes in 22 hours 4 minutes = 1320 + 4 = 1324 minutes.

Whereby the duration of a space walk is up to 5 to 8 hours gives;

22 hours 4 minutes - 8 hour - 8 hour -x = 0

Hence x = 6 hour 4 minutes

Therefore, the duration of each spacewalk is between 6 hour 4 minutes and 8 hours or in minutes we have

The duration of each spacewalk is between  (6 × 60 + 4) 364 minutes and 480 minutes.

7 0
3 years ago
An oblique cylinder with a base of radius 2 units is shown. The top
Anuta_ua [19.1K]

The volume of the cylinder is the amount of space on it

The volume of the oblique cylinder is 174.19 cubic units

<h3>How to determine the volume of the cylinder?</h3>

The given parameters are:

AB = 16 units

Radius (r) = 2 units

\theta = 30^o

Start  by calculating the height (h) using:

h = 16 * \cos(30^o)

This gives

h = 13.86

The volume of the cylinder is then calculated as:

V = \pi r^2 h

This gives

V = 3.142 * 2^2 * 13.86

V = 174.19248

Approximate

V = 174.19

Hence, the volume of the oblique cylinder is 174.19 cubic units

Read more about volumes at:

brainly.com/question/1972490

6 0
2 years ago
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