In the figure above, sin 52=17/c. Based on the figure, which of the following equations is also true
1 answer:
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Please refer to my attachments for visual guidelines.
We are going to solve your problem by using the pythagorean theorem, a^2+b^2 = c^2, where a and b are the legs of the triangle, and c is the hypotenuse (the longest side).
The length of the ladder is equal to 70ft (hypotenuse); one leg is the distance between the wall and the bottom of the ladder - 40 ft, the other leg is unknown for it is the distance between 10 ft above the ground and the top of the ladder-represented by "x". Using pythagorean theorem, a^2+b^=c^2, we have x^2+40^2 = 70^2. Solving the exponents, we have x^2 + 1600 = 4900.
Isolating the variable x, we have x^2 = 4900-1600. Futher simplying, x^2 = 3300. Thus, x = √3300 or 57.4456264654 ft.
Adding 10 ft to x, therefore, the top of the leadder is 67.4456264654 ft off the ground.
We are going to solve your problem by using the pythagorean theorem, a^2+b^2 = c^2, where a and b are the legs of the triangle, and c is the hypotenuse (the longest side).
The length of the ladder is equal to 70ft (hypotenuse); one leg is the distance between the wall and the bottom of the ladder - 40 ft, the other leg is unknown for it is the distance between 10 ft above the ground and the top of the ladder-represented by "x". Using pythagorean theorem, a^2+b^=c^2, we have x^2+40^2 = 70^2. Solving the exponents, we have x^2 + 1600 = 4900.
Isolating the variable x, we have x^2 = 4900-1600. Futher simplying, x^2 = 3300. Thus, x = √3300 or 57.4456264654 ft.
Adding 10 ft to x, therefore, the top of the leadder is 67.4456264654 ft off the ground.
Answer:
$28,342.54
Step-by-step explanation:
The value of an account earning compound interest is found using the formula ...
A = P(1 +r/n)^(nt)
where P is the principal invested at annual rate r compounded n times per year for t years.
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You have P=7000, r=0.12, n=2, t=12.
Using these values in the formula, we find the accumulated value of the investment to be ...
A = 7000(1 +0.12/2)^(2·12) = 7000(1.06^24) ≈ 28,342.54
The value after 12 years is $28,342.54.
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<em>Additional comment</em>
The time-value-of-money functions of your calculator or spreadsheet can find this for you.
