Question

Could someone answer the question with the photo linked below? Then explain how to solve it?

Answer 1

Answer:

Hey there!

Pythagorean Theorem:

$a^2+b^2=c^2$

Let 6 be a, and 11 be b.

$6^2+11^2=c^2$

$36+121=c^2$

$157=c^2$

$\sqrt{157} =c$

Hope this helps :)

Answer 2

Answer:

$12.529$

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2} \\ {6}^{2} + {11}^{2} = {c}^{2} \\ 36 + 121 = {c}^{2} \\ 157 = {c}^{2} \\ \sqrt{157} = {c}^{2} \\ c = 12.529$

$hope \: it \: helps \: < 3$