Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²= 
[∑X₁² - (( ∑X₁)²/n₁)]= 
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!
The nearest degree would be 40
Answer:
300 miles
Step-by-step explanation:
i am doing the same test right now
The answer I believe is 10 calories per minute because 20 x30 =600 I did that because she burned 20 calories per minute so with that being said there’s 60 minutes is the maximum minutes any time can go to so you do 600 divided by 60 which equals 10 which means she burns 10 calories per minute hope this is right
0.024 is 2.4%
0.125 is 12.5%
0.05 is 5%
Showing the workMultiply 0.05 by 100 to convert to percent:
<span>0.05 × 100 = </span>5 %
0.5 is 50%
Showing the work - Multiply 0.5 by 100 to convert to percent:
0.5 × 100 = 50 %
Showing the work -multiply 0.024 by 100 to convert to percent:
0.024 × 100 = 2.4 %
