Question

Help! What is the equation on the graph. I have tried x^2+1 and it marks it incorrect

Answer 1

Answer:

$y=2x^{2}+1$

Step-by-step explanation:

we know that

The graph is a vertical parabola open upward

The vertex is the point (0,1)

The equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^{2}+k$

substitute the vertex in the equation

$y=a(x-0)^{2}+1$

$y=a(x)^{2}+1$

Find the value of coefficient a

Observing the graph

For x=1, y=3

substitute in the equation

$3=a(1)^{2}+1$

$a=3-1=2$

The equation on the graph is equal to

$y=2x^{2}+1$