Answer:
P' (- 7, - 5 )
Step-by-step explanation:
A translation of 3 units to the left means subtractin 3 from the x- coordinate with no change to the y- coordinate, thus
P(- 3, 5 ) → (- 3 - 4, 5 ) → (- 7, 5 )
Under a reflection in the x- axis
a point (x, y ) → (x, - y ), thus
(- 7, 5 ) → P'(- 7, - 5 )
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Answer: 0
Explanation:
I hope this helped!
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- Zack Slocum
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Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer: B
Step-by-step explanation:
24 feet
Set up a ratio of object height to shadow length.
So x/32=6/8
8(4)=32 so 6(4) would be 24.
