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Iteru [2.4K]
3 years ago
9

The restrictions on the variable in the division x+5/x+2 divided by x-3/x+1 are

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
7 0

Answer:

x \neq-2 \text { and } x \neq-1

Step-by-step explanation:

The restricted value is a value that makes the denominator of a function equal to zero. Thus, solving these function results in an undefined solution.

Thus,x \neq-2 and x \neq-1 are the restricted values for \frac{x+5}{x+2} divided by  \frac{x-3}{x+1}

Because, substitutingx=-2 in \frac{x+5}{x+2}

Now, substituting x=-2, we get,

\begin{aligned}\frac{x+5}{x+2} &=\frac{x+5}{-2+2} \\&=\frac{x+5}{0}\end{aligned}

Thus, results the solution undefined.

Also, substituting x=-1 in \frac{x-3}{x+1}  

\begin{aligned}\frac{x-3}{x+1} &=\frac{x-3}{-1+1} \\&=\frac{x-3}{0}\end{aligned}

Thus results the solution undefined.

Hence, the restricted values are  x \neq-2 \text { and } x \neq-1

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viktelen [127]

Answer:

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Step-by-step explanation:

<u>Given</u>

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<u>Step-by-step explanation</u>:

<u>step 1</u> :

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Height or length of the cone,<em> h = 10</em>

<u>step 2</u> :

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*Now u divide 5/5=1 and 61/5=2.5

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