Question

The restrictions on the variable in the division x+5/x+2 divided by x-3/x+1 are

Answer 1

Answer:

$x \neq-2 \text { and } x \neq-1$

Step-by-step explanation:

The restricted value is a value that makes the denominator of a function equal to zero. Thus, solving these function results in an undefined solution.

Thus,$x \neq-2$ and $x \neq-1$ are the restricted values for $\frac{x+5}{x+2}$ divided by  $\frac{x-3}{x+1}$

Because, substituting$x=-2$ in $\frac{x+5}{x+2}$

Now, substituting $x=-2$, we get,

$\begin{aligned}\frac{x+5}{x+2} &=\frac{x+5}{-2+2} \\&=\frac{x+5}{0}\end{aligned}$

Thus, results the solution undefined.

Also, substituting $x=-1$ in $\frac{x-3}{x+1}$  

$\begin{aligned}\frac{x-3}{x+1} &=\frac{x-3}{-1+1} \\&=\frac{x-3}{0}\end{aligned}$

Thus results the solution undefined.

Hence, the restricted values are  $x \neq-2 \text { and } x \neq-1$