$t=v+\frac{k}{g}\\\\v+\frac{k}{g}=t\ \ \ \ |subtract\ v\ from\ both\ sides\\\\\frac{k}{g}=t-v\iff\frac{g}{k}=\frac{1}{t-v}\ \ \ \ |multiply\ both\ sides\ by\ k\neq0\\\\\boxed{g=\frac{k}{t-v}}$

8 0

3 years ago

In the Isoceles triangle, the legs

aalyn [17]

Check the picture below.

since we know that x = 3/7, we can then plug that on either of the twin legs, since it's an isosceles, and get the length of each leg, so say let's plug it in 5x + 16

$5x + 16\implies 5\left( \cfrac{3}{7} \right)+16\implies \cfrac{38}{7}+16\implies \cfrac{38+112}{7}\implies \cfrac{150}{7}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\stackrel{\textit{both legs}}{\cfrac{150}{7}+\cfrac{150}{7}}+\stackrel{\textit{base}}{6}\implies \cfrac{150+150+42}{7}\implies \cfrac{342}{7}\implies 48\frac{6}{7}\impliedby \textit{perimeter}$

3 0

3 years ago