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Vlada [557]
3 years ago
9

What is -2x×18 when x=7​

Mathematics
1 answer:
ahrayia [7]3 years ago
6 0
-2(7)*18
You do -2 times 7 you get an answer then with that number you multiple with 18
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We cant Answer it because the amount of cards presented is incorrect
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at a golf course, a worker placed 216 golf balls equally into 9 buckets. what is the ratio of golf balls to buckets?
ankoles [38]
The ratio is 216:9, which can be simplified to 72:3, which can be simplified to 34:1. This can also be written as a fraction (34/1). It means there are 34 golf balls for every one bucket.
4 0
3 years ago
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16) Total asset turnover is used to evaluate: A. The efficiency of management's use of assets to generate sales. B. The necessit
Mariulka [41]

Answer:

A. The efficiency of management's use of assets to generate sales.

Step-by-step explanation:

The total asset turnover is calculated by dividing the sales to the assets. It measures the ability for a company so that in efficient way it would generate the sales.

By using the assets of the company, the company is able to generate the sales that could help the company for achieving the goals and objectives

Therefore according to the given situation, the a option is correct

6 0
3 years ago
HELP WITH 4 QUESTIONS!!!!
m_a_m_a [10]

When dilation is about the origin, as it is here in every case, the image point coordinates are the original (pre-image) coordinates multiplied by the scale factor.

1. Multiply every coordinate value by 5:

... W' = (-5, 10), X' = (-15, -5), Y' = (25, -5), Z' = (15, 10)

2. Multiply every coordinate value by 1/3:

... A' = (-2, 5), B' = (0, 5/3), C' = (1, 10/3)

3. A' = (2, 8), B' = (6, 2), C' = (2, 2)

4. The image coordinates are 5 times the original coordinates, so ...

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5 0
3 years ago
Given z1 = -3
trasher [3.6K]

Answer:

See explanation

Step-by-step explanation:

The given complex number are:

z_1=-3\sqrt{3}+3i

and

z_2=6\cos 150\degree+6i\sin 150\degree

When we rewrite z_1=-3\sqrt{3}+3i in complex form, we obtain;

z_1=r(\cos \theta+i\sin \theta)

where

r=\sqrt{(-3\sqrt{3})^2+3^2 }=\sqrt{36}=6

and

\theta=tan^{-1}(\frac{y}{x})

\implies \theta=tan^{-1}(\frac{-3\sqrt{3}}{3})=150\degree

Hence,

z_1=6(\cos 150\degree+i\sin 150\degree)

z_1=6\cos 150\degree+6i\sin 150\degree

Hence

z_1=z_2

8 0
3 years ago
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