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Sergio [31]
3 years ago
14

Use the following information to answer the question. A pollotarian is a person who eats poultry but no red meat. A wedding plan

ner does some research and finds that approximately 3.5% of the people in the area where a large wedding is to be held are pollotarian. Treat the 300 guests expected at the wedding as a simple random sample from the local population of about 200,000. Suppose the wedding planner assumes that 5% of the guests will be pollotarian so she orders 15 pollotarian meals. What is the approximate probability that more than 5% of the guests are pollotarian and therefore she will not have enough pollotarian meals? Round to the nearest thousandth. a. 0.421 b. 0.079 c. 0.489 d. None of these

Mathematics
1 answer:
maxonik [38]3 years ago
3 0

Answer:

option b) 0.079

Step-by-step explanation:

The explanation for this question is given in the attachment below.

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From Ash To Sam<br> This is yours
NARA [144]

Answer:

I'll bring Sam here

Step-by-step explanation:

#Nova

4 0
2 years ago
Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?
aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

 two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

  consecutive terms is d, then

  U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

 the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

4 0
4 years ago
gina has 250 in her saving account she puts in 4% of her monthly paycheck of 3,100 each month rodger has 350 in his savings acco
Sidana [21]

<u>Answer:</u>

3 months

<u>Explanation: </u>

Amount saved in Gina’s saving account= 250

Amount Gina puts  in her account each month= 4% of 3100

=\frac{4}{100} \times 3100

= 4 × 31

= 124

Hence total amount  added in each month =124

Therefore money credited x months

= 250 + 124 x

Amount saved in Rodger’s account = 350

Amount Rodger puts in his account each month = 3% of 2900

=\frac{3}{100} \times 290

=87

Hence total amount added in each month = 87

Therefore money credited x months

=350 + 87 x

Now to calculate the nearest month when Gina have more in her account than Rodger does

=Amount of money credited in x months in Gina’s account ≥  Amount of money credited in x months in Rodger’s account

=250+124 x ≥ 350+87 x

=37 x≥100

= x≥2.78

=3

3 0
4 years ago
I don’t understand this either
trasher [3.6K]
It is a part of slope form ( intercept
7 0
4 years ago
Read 2 more answers
Will give brainlist if right
Olegator [25]

Answer:

10/50 = <em><u>20%</u></em>

20% experimental probability

1/5 experimental probability

5 0
3 years ago
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