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otez555 [7]
3 years ago
14

Rodney has a piece of rope that is 82 inches long. Simon has a piece of rope that is 27 inches long. How many longer is Rodney p

iece of rope?
Mathematics
1 answer:
tekilochka [14]3 years ago
5 0
82-27=55, his rope is 55 inches longer
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What percent of 821 is 25?
Anestetic [448]

Answer:

%3.05

Do 25/821 and you should get around 3.05

6 0
3 years ago
The school track has eight lanes. Each lane is 1.25 meters wide. The arc at each end of the track is 180. The distance of the ho
guajiro [1.7K]

Answer:

Part one: r5 = 41.5 m , r6 = 42.75 m , r7 = 44 m , r8 = 45.25  

Part two: Max ran 399.34 m in lane one

Part three: The distance in lanes 3 and 7 are 415.04 m and 446.46 m

Part four: Max ran in the three laps 1260.84 m around the track

Step-by-step explanation:

* lets explain how to solve the problem

- The school track has eight lanes

- Each lane is 1.25 meters wide

- The arc at each end of the track is 180° , that means the arc at each

 end is a semi-circle

- The distance of the home straight for all lanes is 85 m

- The radius of the first lane is 36.5 m

∵ The width of each lane is 1.25

∴ The radius of the second lane = 36.5 + 1.25 = 37.75

- That means the radius of each lane increased by 1.25 then the

  previous lane

∴ The radius of each lane = the radius of the previous lane + 1.25

# Part one:

∵ The radius of the 4 lane is 40.25

∴ The radius of the 5th lane = 40.25 + 1.25 = 41.5 m

∴ The radius of the  6th lane = 41.5 + 1.25 = 42.75 m

∴ The radius of the  7th lane = 42.75 + 1.25 = 44 m

∴ The radius of the  8th lane = 44 + 1.25 = 45.25 m

* r5 = 41.5 m , r6 = 42.75 m , r7 = 44 m , r8 = 45.25  

- The length of each lane is the lengths of the 2 end arcs and  2

   home straight distance

∵ The arc is a semi-circle

∵ The length of the semi-circle is πr

∴ The length of the 2 arcs is 2πr

∵ The length of the home straight distance is 85 m

∴ The length of each lane = 2πr + 2 × 85

∴ The length of each lane = 2πr + 170

# Part two:

- Max ran around lane one

∵ The radius of lane one = 36.5 m

∵ The distance of each lane = 2πr + 170

∴ The distance of lane one = 2π(36.5) + 170 = 399.34 m

* Max ran 399.34 m in lane one

# Part three:

- We will chose lanes 3 and 7

∵ The distance of each lane = 2πr + 170

∵ The radius of lane 3 = 39

∵ The radius of lane 7 is 44

∴ The distance of lane 3 = 2π(39) + 170 = 415.04 m

∴ The distance of lane 7 = 2π(44) + 170 = 446.46 m

* The distance in lanes 3 and 7 are 415.04 m and 446.46 m

# Part four:

- To find the total distance that Max ran in the 3 laps ad the answers

  in part two and part three

∵ Max ran 399.34 m in lane one

∵ Max ran 415.04 m in lane three

∵ Max ran 446.46 m in lane seven

∴ The total distance of the 3 lanes = 399.34 + 415.04 + 446.46

∴ The total distance of the 3 lanes = 1260.84

* Max ran in the three laps 1260.84 m around the track

8 0
3 years ago
Solve -4x^2+3x=-5 using quadratic formula​
Akimi4 [234]

Answer:

Step-by-step explanation:

Here, we want to solve the given quadratic equation using the quadratic formula

We need to rewrite the equation in the standard form;

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we have the value a as -4

value b as 3

C = 5

we then substitute these values into the quadratic formula as seen in the attachment

3 0
3 years ago
Add.<br> (3x + 4) + (5x - 7)
iren2701 [21]
8x-3 calculate your problem on mathaway and you will get a response .
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3 years ago
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How do i find quartiles, 1,2 and 3
Alexus [3.1K]

Lower quartile=25% of total frequency/numbers in the data set

Median=50% of total frequency/numbers in the data set

Upper quartile=75% of total frequency/numbers in the data set

Hope this helps:)

3 0
3 years ago
Read 2 more answers
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