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3 years ago

Help me on this question 20÷10×10

Mathematics

2 answers:

puteri [66]3 years ago

7 0

the answer is 20 because 20/10=2 and 2*10 is 20 so that is why 20 is your answer

serg [7]3 years ago

4 0

Using the order of operations in equations that only contain multiplication and division is fairly simple, just go left to right.

$20/10 = 2\\2*10 = 20\\\\20/10*10 = 20$

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A 30-foot tree casts a shadow that is 6 feet long. A person standing next to the tree casts a shadow that is 1.1 ft long. How ta

melomori [17]

The person is 5.5ft long
Reasoning: 30 divided by 6 equals 5
5 times 1.1 equals 5.5

7 0

2 years ago

276.13 in expanded form

Tcecarenko [31]

200+70+6+1/10+3/100 i think thats the answer

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4 years ago

Read 2 more answers

Parker is laying pavers to build a patio in his backyard. Each square paver measures 2 feet on each side. He would like the pati

Alex787 [66]

Answer:

32 pavers

Step-by-step explanation:

step 1

Find out the area of one square paver

The area of a square is

$A=s^{2}$

where

s is the length side of the square

we have

$s=2\ ft$

substitute

$A=2^{2}\\A=4\ ft^{2}$

step 2

Find out the area of the rectangular patio

we know that

The area of a rectangle is

$A=LW$

we have

$L=16\ ft\\W=8\ ft$

substitute

$A=(16)(8)\\A=128\ ft^2$

step 3

Find out the number of pavers needed to build the patio

Divide the area of the rectangular patio by the area of one paver

$128\ ft^2/4\ ft^{2}=32\ pavers$

3 0

4 years ago

(Differential Equations) Put these equations in explicit form:

Nuetrik [128]

Answer:

1. $y= C(t*exp(-\frac{t^{2} }{2(2!)}+\frac{t^{4} }{4(4!)}-\frac{t^{6} }{6(6!)}+... ))}$

2. $t+C=ln(csc(y)-cot(y)$ $23. [tex]Assuming t as independent variable:F(r,t)=t+\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} =C\\Step-by-step explanation:1. Separable variables:[tex]\frac{dy}{dt}=\frac{y*cos(t) }{t}\\ \frac{dy}{y}= \frac{cos(t) }{t}dt\\ \int {\frac{dy }{y}} \, dt=\int {\frac{cos(t) }{t}} \, dt \\ln(y)-ln(C)=ln(t)-\frac{t^{2} }{2(2!)} +\frac{t^{4} }{4(4!)} -\frac{t^{6} }{6(6!)}+... \\y=C(t*exp(\frac{t^{2} }{2(2!)} +\frac{t^{4} }{4(4!)} -\frac{t^{6} }{6(6!)}+...))$

2. Separable variables

\frac{dy}{sin(y)}=dt\\ \int\ \frac{1}{sin(y)}} \, dy = \int\ 1} \, dt\\t+C=ln(csc(y)-cot(y))[/tex]

3. Homogeneous D.E

Rewriting:

$dr+(\frac{1}{m} exp(m+r)+r)dt=0\\\frac{dF}{dt}=1 -> F(r,t)=t+C(r)\\\frac{dF}{dy}=0+C'(r)= \frac{1}{m} exp(m+r)+r -> C(r)=\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} \\F(r,t)=t+\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} =C\\$

7 0

3 years ago

What is 8x-3y=-16,5x+2y=-41

strojnjashka [21]

I'm assuminng you want to find x and y

eliminate

hmm
eliminate y's
3 times 2=6

multiply first equation by 2 and 2nd by 3 and add

16x-6y=-32
<u>15x+6y=-123 +</u>
31x+0y=155

31x=155
divide both sides by 31
x=5
sub back

5x+2y=-41
5(5)+2y=-41
25+2y=-41
minus 25 both sides
2y=-66
divide by 2
y=-33

(x,y)
(5,-33)

5 0

3 years ago