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Anettt [7]
3 years ago
6

Evaluate 8a-1+0.5b8a−1+0.5b8, a, minus, 1, plus, 0, point, 5, b when a=\dfrac14a=

Mathematics
2 answers:
professor190 [17]3 years ago
7 0

Answer: 6

Step-by-step explanation:

Given the following expression:

8a-1+0.5b

You need to substitute the given values of "a" and "b" into the expression. Notice that these values are:

a=\frac{1}{4}\\\\b=10

Then;

 8a-1+0.5b=8(\frac{1}{4})-1+0.5(10)

Now you must solve the multiplications:

=\frac{8}{4}-1+5=2-1+5

The final step is to add the numbers. Therefore, you get the following answer:

=6

mart [117]3 years ago
5 0

Answer: 6

Step-by-step explanation:

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Use the formula of the present value of an annuity ordinary which is
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Pv present value 5500
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write the equation in slope intercept form of the line that passes through -1, 11 and is parallel to the graph of y = -8x + 3
lawyer [7]
<h2>Answer: The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ). </h2>

<h3 /><h3>Step-by-step explanation: </h3>

<u>Find the slope of the parallel line</u>

When two lines are parallel, they have the same slope.

                 ⇒  if the slope of this line = - 8

                      then the slope of the parallel line (m) = - 8

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:  

                               ⇒  y - 11  =  - 8 (x - (-1))                                

                                ∴  y - 11  = - 8 (x + 1)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

                      since   y - 11  = - 8 (x + 1)

                                        y  = - 8 x  + 3

The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ).

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2 years ago
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