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ddd [48]
3 years ago
8

Y=2x+12 and y=-x-9 in graph form.

Mathematics
1 answer:
fomenos3 years ago
8 0
All work shown, I hope that this works!

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A certain radioactive isotope decays at a rate of 2% per 100 years. if t represents time in years and y represents the amount of
gregori [183]
We rewrite the equation:
 y = y0 * e ^ (- 0.0002 * t)
 In this equation:
 I = represents the initial amount of the isotope
 We have then:
 89% of the isotope left:
 0.89 * y0 = y0 * e ^ (- 0.0002 * t)
 We clear the time:
 e ^ (- 0.0002 * t) = 0.89
 Ln (e ^ (- 0.0002 * t)) = Ln (0.89)
 -0.0002 * t = Ln (0.89)
 t = Ln (0.89) / (- 0.0002)
 t = 582.6690813
 round to the nearest year:
 t = 583 years
 Answer:
 
There will be 89% of the isotope left in about:
 
t = 583 years
7 0
3 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
1 year ago
Help please.........
IrinaVladis [17]
Im on sure but probably 0.75
7 0
3 years ago
Read 2 more answers
ANSWER THIS TO GET 23 POINTS AND BRAINLIEST
puteri [66]

<em>Ohhh, interest problems. I haven't done an equation like this in a long time, but I will attempt.</em>

<em>I would say that the answer is the 2nd option. The equation is i = (5200)(0.06)(2.5).</em>

<em>The traditional interest formula is I = (P)(R)(N).</em>

<em>P = the original amount of money given</em>

<em>R = interest rate</em>

<em>N = the amount of time</em>

<em />

<em>I hope this answers your question (and that I understood the question correctly!).</em>

<em>-Toremi</em>

6 0
2 years ago
A right triangle has a hypotenuse of 43cm and an angle of 56 degrees opposite leg m . What is the length of leg m rounded to the
Alika [10]

Answer:

you are my idol

Step-by-step explanation:

Keep working. Karma is real

6 0
3 years ago
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