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3 years ago

9

What is the solution to this equation? 8x - 5 (x-3) = 18

1 answer:

Kaylis [27]3 years ago

3 0

Answer:

x=1

Step-by-step explanation:

We distribute the negative 5 to x minus three to get 8x-5x+15=18. Then, we cancel out the 15 by subtracting it from both sides. This leaves us with 8x-5x=3. When we subtract, we get 3x=3, and when we divide both sides by 3, we get x=1. Hope this helps :)

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Which of the following is a true equation?<br> k=y/x<br> k= x/y<br> x= y/k

faust18 [17]

Answer:

Step-by-step explanation:

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7 0

3 years ago

The length of a rectangle is the width minus 8 units. The area of the rectangle is 9 units. What is the length, in units, of the

frez [133]

Length of rectangle is 1 unit

<u>Solution: </u>

Given that

Length of a rectangle is width minus 8 units.

Area of rectangle = 9 square units

Need to calculate the length of rectangle.

Let us assume width of rectangle = x

As Length is width minus 8,

Length of the rectangle = x – 8

$\text{ Area of rectangle }=\text{ width of rectangle }\times \text{ Length of the rectangle }$

$\text{ Area of rectangle }= x\times (x-8)$

$\text { Area of rectangle }=\left(x^{2}-8 x\right)$

As given that area of rectangle = 9 square units

$\begin{array}{l}{\Rightarrow x^{2}-8 x=9} \\\\ {\Rightarrow x^{2}-8 x-9=0}\end{array}$

On solving above quadratic equation for x, we get

$\begin{array}{l}{\Rightarrow x^{2}-9 x+x-9=0} \\\\ {\Rightarrow x(x-9)+1(x-9)=0} \\\\ {\Rightarrow (x-9)(x+1)=0}\end{array}$

When $x-9 =9, x = 9$

When $x + 1 = 0, x = -1$

As width cannot be negative, so considering x = 9

$\text{ Length of rectangle }= x-8 = 9-8 = 1 \text{ unit }$

Hence, Length of rectangle is 1 unit.

5 0

3 years ago

3(x – 2) – 2x + 3 = -12

enyata [817]

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