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3 years ago

6

Which describes the amgle

2 answers:

Dmitry [639]3 years ago

4 0

If you follow the arrow, it's C, 3/4 turn

Sati [7]3 years ago

3 0

The answer is
A.) 1/4 of a turn

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What is 1.5 as a whole number?

Masteriza [31]

Answer:

2

When the decimal is 5 or more, the number is rounded up by converting it into the next whole number.

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3 years ago

Read 2 more answers

a teacher plans for groups of her students to eat lunch at tables. she has 34 students in her class. each group will have 7 stud

S_A_V [24]

To find the answer for this word problem you can start by dividing 34/7
You will find yourself with 4 tables that can fit 7 students and 6 studebts will have to sit at a table because they are the ones left.
So there will be 4 tables full of 7 seven students each and one table with 6 students.

Please vote my answer brainliest. Thanks!

7 0

3 years ago

For which equations is x = 9 a possible solution? Check all that apply. |x| = 9 –|x| = 9 –|–x| = 9 –|–x| = –9 |x| = –9 |–x| = 9

saul85 [17]

Answer:

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3 years ago

Which best describes the slope of the given line?

dolphi86 [110]

Answer:

undefined

Step-by-step explanation:

The line shown is a vertical line

A vertical line has a slope of undefined

8 0

3 years ago

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

Sum of squares of differences = 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

Population mean, μ = $30,000

Sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

Now,

$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0

4 years ago