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attashe74 [19]
3 years ago
13

Pythagorean Theorem #2

Mathematics
2 answers:
lora16 [44]3 years ago
8 0

Answer:

b = 4 sqrt(2)

Step-by-step explanation:

We can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

2^2 + b^2 = 6^2

4 + b^2 =36

Subtract 4 from each side

4-4 + b^2 = 36-4

b^2 = 32

Take the square root of each side

sqrt(b^2) = sqrt(32)

b = sqrt(32)

b = sqrt(16*2)

We know that sqrt(x*y) = sqrt*x) sqrt(y)

b = qrt(16)sqrt(2)

b = 4 sqrt(2)

Nataly_w [17]3 years ago
6 0

Answer:

4 square root 2

Step-by-step explanation:

the pythagorian theorem will look like this: 2^2+b^2=6^2

simpify: 4+b^2=36

get b by itself by subtracting four from each side: b^2=32

take the square root of 32 and simplify: 4sqrt2

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