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iragen [17]
3 years ago
5

Soccer ball profit

Mathematics
2 answers:
Nady [450]3 years ago
5 0

Answer:

$8.33 per soccer ball.

Step-by-step explanation:

Y max is =236.67   is the max profit from the soccer balls. This goes on when you charge 8.33 a ball

eimsori [14]3 years ago
5 0

Answer:

need to solve the equation 150 = -6x2 + 100x - 180. I can subtract 150 from both sides and use the quadratic formula to find x = 4.53 and 12.13. This means that if the store sells soccer balls for $4.53 or $12.13, it will earn a daily profit of $150.

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9 in. 14 in. Find the area of the triangle shown above. [?] square inches​
mamaluj [8]

Answer:

63

Step-by-step explanation:

9 x 14 = 126/2 = 63

7 0
3 years ago
NEEED HELPPPP
Vitek1552 [10]
For the answer to the question above, it is -18% because to find rate we subtract the rate, in this case, is .82 or 82% - 1 or 100% and that would give you the rate, in this case, its decreasing by an 18%
I hope my answer helped you.
3 0
4 years ago
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Moe, Curly, and Larry are brothers. Moe is the youngest brother, white Larry is the oldest brother. Their ages are consecutive i
damaskus [11]

Answer:

middle brother = x

older brother = x+1

younger brother = x-1

x-1+x+x+1=129

3x+0=129

3x=129

x = 43(middle brother)

43-1 = 42(younger brother)

43+1 = 44(elder brother)

Check:

43-1+43+43+1=129

42+43+44=129

129=129

4 0
3 years ago
Find the area of the square above using its net below. 5
Alborosie

Answer:

150 units

Step-by-step explanation:

first, find 1 square

5 x 5 = 25

there are 6 total squares so 25 x 6 = 150

So the surface area should be 150 units

6 0
3 years ago
The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
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