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3 years ago

2. If you used the 23 cm basketball as your Moon sphere, how big

1 answer:

6 0

Ok so I heard this question a few times already and couldn't remember how it went so I decided to put my brain to the test, I used my algebra to use and complete it.

If the Earth were shrunk down to the size of a basketball (radius:4.69 inches) the Moon would be a tennis ball (radius: 1.2768 inches, to be exact) 23.5 feet away.

The Sun would be a 42.6-foot sphere (source) located 1.7 miles away.

The closest star, Proxima Centauri, would still be 463,151 miles away – almost twice the distance of the actual moon."

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( a+b )^2 = ...........................

stepladder [879]

Answer:

$a^{2} + 2ab +b^{2}$

5 0

3 years ago

Read 2 more answers

If today you can buy more Euros with $100 CAD than yesterday has the euro increased or decreased in value against the CAD?

Ksenya-84 [330]

Decreased as getting more for less/same amount makes it so the worth of euro has went down

8 0

3 years ago

A group of 18 people ordered soup and sandwiches for lunch. Each person in the group either ordered one soup or one sandwich . T

kkurt [141]

Let's say a = number of ordered soups, b = number of ordered sandwiches.

Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.

How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.

If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.

10*7.75 + 8*4.50 = 113.50

8 0

4 years ago

Identify the quotient in the form a + bi. HELP ASAP PLEASE!!

Step2247 [10]

Solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression: $\frac{4-5i}{2+3i}$

Multiplying and dividing by 2-3i

$=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}$

So, solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

#learnwithBrainly

8 0

3 years ago

You randomly choose one marble from the jar. Find the theoretical probability of the event.

zysi [14]

Answer:

1. 33%

2. 16%

3. 50%

Step-by-step explanation:

4 0

3 years ago