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Vitek1552 [10]
3 years ago
10

Do not under stand got confused and need help

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0
For #3, you just have to plug in the numbers for x.
It tells you what to substitute for x in the question. (x = 0, 1, 2, 3, 4, 5, and 6)

For example, let's substitute 0 for x.
6x - x² (the 2 means square the number, or multiply it by itself)
6(0) - (0)²
0 - 0
= 0.

You'll do that to all the numbers (1-6) and fill out the table.

For #4, you have to solve using the distributive property to find out if the equations on both sides are equal.

I'll do the first one for you.

6a - 8 = 2 (3a - 5)
6a - 8 = 6a - 10
They're not equal.
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Question from my math test
frutty [35]

Answer:

The manager skipped June

Step-by-step explanation:

In the first bar we can see the sales are from

January - February

Then,

March - April.

But then, the store manager goes from

May - July,

and totally skipped June, therefore making it look like the sales have increased.

4 0
2 years ago
Can someone help meee
pickupchik [31]

Step-by-step explanation:

29+1/5r=

29+(1/5×-1/2)

29+1/10

291/10

=29.1

4 0
2 years ago
Read 2 more answers
The diagonals of a rhombus are 21 m and 32 m. What is the area of the rhombus?<br> 30 POINTS
Wittaler [7]
I have included attachment below

so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
area of rectangle=legnth times width=16 times 21=336 m^2

answer is 336 m^2

5 0
2 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
4 1/12 + 1 3/4 = ?<br> Fractions please help I'm tired.
AfilCa [17]

Lets just convert them into improper fractions.

1) 4 and 1/12 = 49/12.

1 and 3/4 = 7/4.

2) 7/4 = 21/12

3) 21/12 + 49/12 = 70/12

Back to mixed fractions!

70/12 = 5 and 10/12 = 5 and 5/6

=5 5/6

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

There is another method if you want to know. You can simply just do 4 + 1 = 5. Then do 1/12 + 3/4 = 10/12 = 5/6. So it goes to 5 5/6. Your choice which ever you find more eas.

7 0
2 years ago
Read 2 more answers
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