Question

Michelle spent $32 on hot dogs and hamburgers. Hot dogs were $5 and hamburgers $6.if she bought a total of 6 items .how many of each kind did she buy?
A. 2 hot dogs and 4 hamburgers
B. 4 hot dogs and 2 hamburgers
C. 6 hot dogs and 0 hamburgers
D. 3 hot dogs and 3 hamburgers

Answer 1

The answer is B 4 hot dogs = $20 and two hamburgers = $12 so 20 plus 12 equals 32 so the answer is B

Answer 2

Answer:

Option (b) is correct.

Michelle buys 4 hot dogs and 2 hamburgers.

Step-by-step explanation:

Given : Michelle spent $32 on hot dogs and hamburgers. Hot dogs were $5 and hamburgers $6.if she bought a total of 6 items .

We have to find the number of each item she buys.

Let she buys x hotdogs and y hamburger

Given she buys 6 items

So, x + y = 6

and cost of one hot dog is $5

so , cost of x hot dog is 5x

also, cost of one hamburger is $6

so , cost of y hamburger is 6y

Given : she spent $32 on both

Thus, 5x + 6y = 32

Thus, The two equation becomes,

x + y = 6  ..(1)

and 5x + 6y = 32  ......(2)

Solving system using elimination method,

multiply equation (1) by 6 ,we get,

6x + 6y = 36 ....(3)

Now, subtract (2) from (3), we have ,

6x + 6y - (5x + 6y) = 36 - 32

Simplify, we have,

x = 4

Put x= 4 in (1), we have,

y = 6 - 4

y= 2

Thus, Michelle buys 4 hot dogs and 2 hamburgers.