C. translated down 2 units
---The "-2" located on the outside of f(x) tells us that the y-values are being changed. With that, the graph can be moved up or down. The presence of the negative/subtraction sign tells us that the graph is moved down.
D. translated right 4 units
---The "-4" located with the x in f(x) tells us that the x-values are being changed. The only tricky thing about this is that the direction of the movement is actually the opposite of the sign. So with the negative/subtraction sign, the graph is moved to the right instead of the left.
Hope this helps!
Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
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The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21
Step-by-step explanation:
Since AC=BE & DE=DC
then measure angle <CAD=<EBD =X
Then< DAB =90-x
And <ABD= 90-X
then measure angle 1= measure angle 2
