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bagirrra123 [75]
3 years ago
7

NEED ASAP!!!!

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
3/10 x 2/2= 6/20
1/2 x 8/8 = 16/24
1/1 x 5/5= 5/5
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The lateral surface area of a cylinder is given by the formula S=2 \pirh. Solve the equation for r.
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S = 2 * (pi) * r * h.....for r
divide both sides by 2 * pi * h
s / (2(pi)h = r

8 0
3 years ago
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How do your write 1 2/14 as a decimal
Goshia [24]
I  believe the answer would be 1.17
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Graph g is a translation of the graph of y= sin x (dashed line).a) write down the equation of g b) write down the coordinates of
labwork [276]

Answer:

<em>a)  </em>G(x)= \sin x + 2<em />

<em>b) The coordinates of P are</em>

<em />\displaystyle \left( \frac{3\pi}{2},1\right)

Step-by-step explanation:

<u>Translation</u>

The dashed line shows the graph of the function

y = \sin x

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.

a)

Graph G shows the same function but translated by 2 units up, thus the equation of G is:

\boxed{G(x)= \sin x + 2}

b) The coordinates of P correspond to the value of

x = \frac{3\pi}{2}

The value of G is

\displaystyle G(\frac{3\pi}{2})= \sin \frac{3\pi}{2} + 2

Since

\sin \frac{3\pi}{2}=-1

\displaystyle G(\frac{3\pi}{2})= -1+ 2=1

The coordinates of P are

\displaystyle \left( \frac{3\pi}{2},1\right)

8 0
3 years ago
A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.
KIM [24]

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Answer:

  • absolute error: 0.4 kg
  • relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

  7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

__

The relative error is the ratio of the absolute error to the actual weight:

  (0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0
3 years ago
Find the center of the circle that can be circumscribed about EFG with E(4, 4), F(4, 2), G(8, 2). (3, 6) (4, 2) (4, 4) (6, 3)
Lesechka [4]

Answer:

(6,3)

Step-by-step explanation:

8 0
3 years ago
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