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bagirrra123 [75]
3 years ago
7

NEED ASAP!!!!

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
3/10 x 2/2= 6/20
1/2 x 8/8 = 16/24
1/1 x 5/5= 5/5
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8x –3(5x–2)=7–10x <br><br> Solve this equation with a clear value for x
Serga [27]

Answer:

x = 1/3

Step-by-step explanation:

8x –3(5x–2)=7–10x

Distribute

8x - 15x +6 = 7-10x

Combine like terms

-7x + 6 = 7- 10x

Add 10x to each side

-7x +10x+ 6 = 7- 10x+10x

3x+6 = 7

Subtract 6 from each side

3x+6-6 =7-6

3x = 1

Divide each side by 3

3x/3 = 1/3

x = 1/3

8 0
3 years ago
Read 2 more answers
find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0​
Vlad1618 [11]

Answer:

Step-by-step explanation:

line given is x-y+1= 0

you can rewrite it in slope intercept y=mx+b where m is the slope, and b is the y-intercept where the line meets the y-axis

x-y+1 =0 subtract x and 1 from both sides of the equation

-y = -x-1 multiply both sides by -1

y = x+1 so the slope of this line is 1 and the y-intercept is 1

If you draw this line you can see that there are actually 2 lines that form 45° angles with y=x+1 and pass through (-1, 2), one is vertical x= -1 and one horizontal y =2

8 0
3 years ago
Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
Assuming that x=-2 and y=3 evaluate xy-x^3 ​
meriva
(-2^3) = -8.
-2 times 3 = -6.

The expression is now -6 - (-8).

-6 + 8 = 2.

The answer should be 2.
4 0
2 years ago
Jenny bought a $50 jacket. If the sales tax rate is 8%, how much tax did she pay?
OlgaM077 [116]

Answer:

54$

Step-by-step explanation:

  • To get the tax times the number to the percentage
  • 50 * 8% = 4
  • 50 + 4 = 54 $
8 0
2 years ago
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