Option D:
is the function
Explanation:
Let the general form of quadratic equation be 
The function passes through the intercepts
and
and also passes though the point 
Substituting the points
,
and
in the equation
, we get,
-----------(1)
----------(2)
-----------(3)
Subtracting (1) and (2), we get,
-----------(4)
Subtracting (2) and (3), we get,
------------(5)
Multiplying equation (4) by 5 and equation (5) by 4, to cancel the term b when adding, we get,

Thus, the value of a is 
Substituting
in equation (4), we get,

Thus, the value of b is 
Now, substituting the value of a and b in equation (1), we have,

Thus, the value of c is 
Now, substituting the value of a,b and c in the general formula
, we get,

Taking out the common term as -2 we get,

Factoring , we get,

Thus, the function is 