( –6m^7 + 20m^6<span>) ÷ 2m^4 = ???
as you know
</span> –6m^7 + 20m^6 = 2m^4 (-3m^3 + 10m^2)
[2m^4 (-3m^3 + 10m^2) ] / 2m^4 (2m^4 is canceled out)
= -3m^3 + 10m^2
answer is B. –3m^3 + 10m^2
6<span>√2 is already in it's simplest form as a radical.
</span>
Answer:
Options: A, B, and C correctly solve for x.
Step-by-step explanation:
A).
= 
Multiplying both sides by 2 gives;
5x = 15
x = 15 ÷ 5 = 3
∴ This option correctly solve for x.
B).
x +
= 7
x = 7 -
= 
∴ This option correctly solve for x.
C).
x + 3 = 
x = 
But the option give x as 5/6 hence this option does not correctly solve for x.
D).
5x = 11/2
x = 11/2 ÷ 5 = 11/2 × 1/5 = 11/10
But the option gives x as 10/11 so it does not correctly solve for x.