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liberstina [14]
3 years ago
9

Answer PLS i'm Desperate

Mathematics
2 answers:
Murrr4er [49]3 years ago
4 0

Answer:

12.56

Step-by-step explanation:

The shape is 1/4 of a circle.

The arc length is 1/4 of the whole circle’s circumference.

C=3.14 \times d

r=8

d=2r\\d=2(8)\\d=16

1/4 \times 3.14 \times 16

=12.56

mezya [45]3 years ago
3 0

Answer:

12.56

Step-by-step explanation:

1. Circumference equation: 2πr

2. Substitute radius in equation: 2•8π

3. Simplify: 16π, or 50.24

4. Divide by 4, since you only need to find 1/4 of the circumference: 12.56

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Please help , ayudame Por favor
Mumz [18]

Answer:

Line segment AD

AD = \sqrt{(c-0)^{2}+(d-0)^{2}}

AD = \sqrt{c^{2}+d^{2}}

Line segment BC

BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}

BC = \sqrt{c^{2}+d^{2}}

Line segment AB

AB = \sqrt{(b-0)^{2}+(0-0)^{2}}

AB = \sqrt{b^{2}+0^{2}}

AB = b

Line segment CD

CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}

CD = \sqrt{b^{2}+0^{2}}

CD = b

Step-by-step explanation:

We defined the length of each side by the Equation of the Line Segment, which is a particular case of the Pythagorean Theorem. Let A(x,y) = (0,0), B(x,y) = (b,0), C(x,y) = (b+c, d) and D(x,y) = (c,d), we construct the equations below:

Line segment AD

AD = \sqrt{(c-0)^{2}+(d-0)^{2}}

AD = \sqrt{c^{2}+d^{2}}

Line segment BC

BC = \sqrt{[(b+c)-b]^{2}+(d-0)^{2}}

BC = \sqrt{c^{2}+d^{2}}

Line segment AB

AB = \sqrt{(b-0)^{2}+(0-0)^{2}}

AB = \sqrt{b^{2}+0^{2}}

AB = b

Line segment CD

CD = \sqrt{[c-(b+c)]^{2}+(d-d)^{2}}

CD = \sqrt{b^{2}+0^{2}}

CD = b

6 0
3 years ago
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Serggg [28]

The answer is x - 5

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kondor19780726 [428]

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So 12^2+16^2=c^2

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square root of 400=c

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7 0
3 years ago
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There are two pencils.One is 14 cm long,the other is x cm if x=10, what is the total length of the two pencils​
Crank

Answer:

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Answer:

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