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andre [41]
4 years ago
5

Corey and Jack share money in the ratio of 8 : 5If Jack has $75 how much does Corey have?

Mathematics
1 answer:
mixas84 [53]4 years ago
6 0

Answer:

120

Step-by-step explanation:

8:5

x:75

ratio problem

8/x = 5/75

5x = 600

x = 120

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KonstantinChe [14]

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0.75 is it  the answer

Step-by-step explanation:

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Pls PLS solve T_T i tried everything ​
Rudik [331]

Answer:

12√3 is the correct answer

6 0
3 years ago
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I need help, the options are: Corresponding Angles, Vertical Angles, Alternate interior angles, linear pair, alternate exterior
stiks02 [169]

Answer:

✔️ <1 and <3 => Vertical angles

✔️<2 and <6 => alternate exterior angles

✔️<2 and <4 => corresponding angles

✔️<3 and <7 => alternate interior angles.

✔️<4 and <3 => consecutive interior angles.

✔️<7 and <6 => linear pair angles.

Step-by-step explanation:

✔️ <1 and <3 are opposite angles formed when two straight lines intersect. They both share the same vertex. Thus, they are vertical angles, which are congruent to each other.

<1 and <3 are vertical angles.

✔️<2 and <6 are alternate exterior angles.

<2 and <6 both lie outside the straight lines cut across by the transversal, and they also lie in the side of the transversal alternating each other

✔️<2 and <4 are corresponding angles.

They both take the same position on the same side of the transversal.

✔️<3 and <7 are alternate interior angles.

They are alternating angles along the transversal that are located just within the two lines intersected by the transversal.

✔️<4 and <3 are consecutive interior angles.

They are angles on the same side of the transversal but lie within the two straight lines intercepted by the transversal.

✔️<7 and <6 are linear pair angles.

They are angles on a straight line, and sum up to 180°.

3 0
3 years ago
One square megameter is equal to 1.0×106 square kilometers. How many square megameters are in 9,000,000 square kilometers?
Firlakuza [10]
9, because one square megameter is equal to one million square kilometers.
7 0
3 years ago
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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
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