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Akimi4 [234]
4 years ago
15

What exponential function is the best fit for the data in the table?

Mathematics
1 answer:
Nonamiya [84]4 years ago
6 0

Answer:

   f(x)=1/4(4)^(x-1) -4

Step-by-step explanation:

The negative value for x=2 tells you that the vertical offset cannot be positive. That rules out the 1st and 3rd choices.

You can try x=2 in the remaining functions to see which works:

  f(2) = 4(4^(2-1)) -4 = 12 ≠ -3 . . . . . . . . the 2nd choice does not work

  f(2) = (1/4)(4^(2-1) -4 = -3 . . . . . . . . . . the 4th choice matches the table

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Answer:

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6 0
3 years ago
The proceeds from a car wash are directly proportional to the number of cars washed. the total after 9 cars was $180.
Tatiana [17]

Answer:

a) 1200

b) 75

Step-by-step explanation:

6 0
3 years ago
A taxi hurries for 1 hour 54min with a constant speed of 93km and then for another 5 hours 15min with a constant speed of 72km.
Ghella [55]

Speed  = 93km /h  and  72km/h

Answer: The taxi went a distance of 554.7km

Step-by-step explanation:

Speed  = Distance / Time

Distance covered in the first trip = Speed x Time

Time = 1 hour 54 min =1+0.9 hours  =1.9hours

=93km / h x 1.9 hours =176.7km

Distance covered in the second  trip = Speed x Time

Time = 5 hours 15min = 5+0.25hours  =5.25hours

=72km / h x 5.25hours =378 km

Total distance =176.7km+378 km

=554.7km

6 0
3 years ago
What is the measure of the unstable Angle of the triangle below?
Arlecino [84]
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6 0
3 years ago
A coin is tossed 71 times and 34 heads are observed. Is the coin fair? Use a 98% level confidence interval to base your inferenc
Fofino [41]

Answer:

a) \hat p=\frac{34}{71}=0.48 estimated proportion of heads observed.

b)  Se= \sqrt{\frac{0.479(1-0.479)}{71}}=0.0593

c) z_{\alpha/2}=2.33

d) 0.479 - 2.33 \sqrt{\frac{0.479(1-0.479)}{71}}=0.341

e) 0.479 + 2.33 \sqrt{\frac{0.479(1-0.479)}{71}}=0.617

f) In order to be fair the coin needs to have included the 0.5 on the interval, and for this case it's included, so we can say that at 2% of significance we can say that the coin is fair.

Step-by-step explanation:

Notation and definitions

X=34 number of heads observed.

n=71 random sample taken

\hat p=\frac{34}{71}=0.479 estimated proportion of heads observed.

p true population proportion of heads observed.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The point estimator for the population proportion of heads is: Answer with two decimal precision.

\hat p=\frac{34}{71}=0.48 estimated proportion of heads observed.

The standard error in this estimate is: Answer with four decimal precision.

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And the standard error is given by:

Se= \sqrt{\frac{\hat p(1-\hat p)}{n}}

Se= \sqrt{\frac{0.479(1-0.479)}{71}}=0.0593

The correct table value for the 98% level confidence interval is: Answer with two decimal precision

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.33

The lower end point of the CI is: Answer with three decimal precision.

And replacing into the confidence interval formula we got:

0.479 - 2.33 \sqrt{\frac{0.479(1-0.479)}{71}}=0.341

The upper end point of the CI is: Answer with three decimal precision.

0.479 + 2.33 \sqrt{\frac{0.479(1-0.479)}{71}}=0.617

And the 90% confidence interval would be given (0.341;0.617).

Based on the confidence interval, it is plausible that the coin is fair.

In order to be fair the coin needs to have included the 0.5 on the interval, and for this case it's included, so we can say that at 2% of significance we can say that the coin is fair.

4 0
4 years ago
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