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3 years ago

Forecast error is found by subtracting the forecast from the actual demand for a given period. True or False

Physics

2 answers:

Burka [1]3 years ago

7 0

Answer:

The correct option is;

True

Explanation:

The forecast error provides the estimates of the level of deviation of the forecast from the observed actual demand within a period under study

The forecast error is defined as the difference between the observed actual demand and the forecast demand expressed as a percentage or an absolute value.

Forecast error determination is important to judge the accuracy of a given demand forecast within a specified time frame.

Forecast error is expressed as

Et = Dt - Ft

Where:

E = Forecast error

F = Forecast

D = Demand

t = Time.

kap26 [50]3 years ago

5 0

Answer:

True

Explanation:

Forecast error can be referred to as the deviation of the actual demand from the forecasted or predicted demand.

In other words, it is the difference between the actual or real and the predicted or forecast value of a time series.

From the definition, we understand that forecast error is all about how much is the difference between what's is been forecasted and the actual value.

Mathematically,

Forecast Error = Actual Value of Demand - Forecasted Value of Demand.

Irrespective of whether the actual prediction is smaller or not; on a more standard term, it is calculated as follows

Forecast Error = ABS (Actual – Forecast)

Where ABS = the absolute value of....

And it always returns a positive value of the expression in brackets

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A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for

nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block ( $W$ ), measured in newtons, is:

$W = m\cdot g$ (1)

Where:

$m$ - Mass of the block of ice, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 14\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the magnitudes of the weight and normal force of the block of ice are, respectively:

$N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$N = W = 137.298\,N$

And the pull force is:

$F_{pull} = 98\,N$

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

$m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}$ (2)