Answer:
D
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Explanation:
D
The pH of blood if pco2 drops to 35.0 mmHg is 7.459
The pH of the blood can be calculated using the Henderson- Hasselbalch equation, which explains the relationship between acid dissociation constant pKa and pH in biological and chemical systems.
pH = pK + log ( HCO3- / ( 0.03 * PCO2 ) )
pK is 6.1 for the bicarbonate buffer system.
HCO3- = 24mm
PCO2 = 35.0 mmhg
pH = 6.1 + log ( 24 / 0.03 * 35.0 )
= 6.1 + log ( 24 / 1.05 )
= 6.1 + log 22.8571
= 6.1 + 1.3590
= 7.459
Hence, the pH of blood is 7.459
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The stages of mitosis are:
1. Prophase
2. Metaphase
3. Anaphase
4. Telophase<span>
Prophase
This is when the </span><span>centrioles separate and move to opposing sides of the cell.
Metaphase
This is when the chromosomes line up in the center of the cell and become connected.
Anaphase
This is when the</span><span> "sister" chromatids separate into individual chromosomes and are pulled apart.
Telophase
This is the last phase of mitosis, when chromosomes gather at opposite ends of the cell and new nuclear membranes form.
The answer is metaphase, because that is when the chromatids line up in the center of the cell.
Answer:
Metaphase</span>
