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____ [38]
3 years ago
8

an equation and the steps to solve it are shown below: 3x − 1 over 2 (8x − 2) = 4 step 1: 3x − 4x 1 = 4 step 2: x 1 = 4 step 3:

x 1 − 1 = 4 − 1 step 4: x = 3 which step was the error made and why? a.) step 1, because incorrect signs have been used b.) step 2, because the terms have been added incorrectly c.) step 3, because numbers have been added to both sides of the equation d.) no error was made
Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0
3x - 1/2(8x - 2) = 4
3x - 4x + 1 = 4
-x + 1 = 4
-x + 1 - 1 = 4 - 1
-x = 3
x = -3

Mistake was made in step 2, because the terms have been added incorrectly.
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Answer:

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Step-by-step explanation:

What you have to do to get the answer is find out what 10^4 is, and then multiply that by 2.78. After that, you just need to divide it by 50.

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2.78 × 10,000 = 27,800

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Leni [432]

Answer:

<h3>The statements i) x+y=y+x</h3><h3> ,iv) (x+y)+z=x+(y+z)</h3><h3>and v) (x-y)-z = x-(y-z) are true </h3>

Step-by-step explanation:

Given that  x = a + bi and y = c + di and z = f + gi

<h3>To check which statements are true :</h3><h3>i)x+y=y+x</h3><h3>Taking LHS x+y</h3>

Substitute the values of x and y we get

x+y=a+bi+c+di

<h3>x+y=(a+c)+(b+d)i=LHS</h3><h3>Taking RHS y+x</h3>

Substitute the values of x and y we get

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<h3>Therefore x+y=y+x statement is true </h3><h3>iv) (x+y)+z=x+(y+z)</h3><h3>Taking LHS (x+y)+z</h3>

Substitute the values of x ,y and z we get

(x+y)+z=(a+bi+c+di)+(f+gi)

<h3>(x+y)+z=(a+c+f)+(b+d+g)i=LHS</h3><h3>Taking RHS x+(y+z)</h3>

Substitute the values of x ,y and z we get

x+(y+z)=(a+bi)+(c+di+f+gi)

<h3>x+(y+z)=(a+c+f)+(b+d+g)i=RHS</h3>

Therefore LHS=RHS

<h3>Therefore  statement (x+y)+z=x+(y+z) is true</h3><h3>v) (x-y)-z = x-(y-z)</h3><h3>Taking LHS (x-y)-z</h3>

Substitute the values of x ,y and z we get

(x-y)-z=(a+bi-(c+di))-(f+gi)

=a+bi-c-di-f-gi

<h3>(x-y)-z=(a-c-f)+(b-d-g)i=LHS</h3><h3>Taking RHS x+(y+z)</h3>

Substitute the values of x ,y and z we get

x-(y-z)=(a+bi)-((c+di)-(f+gi))

x-(y-z)=a+bi-c-di-f-gi=RHS

Therefore LHS=RHS

<h3>Therefore  statement (x-y)-z=x-(y-z) is true</h3><h3>Therefore the statements i) ,iv) and v) are true </h3><h3 />
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