<u>Answer</u>:
Organic molecules present in chicken are Nucleic acid, proteins, carbohydrate and lipids
.
<u>Explanation</u>:
Chicken itself has the all four organic molecules in it. Organic molecules are those having carbon in it. They are attached by covalent bonds, in which electrons are being shared within the atoms. The nucleic acids are DNA and RNA which helps in the making of the proteins which are found in the various structure and ought to perform various metabolic functions. Proteins are the building block of the amino acids. Lipids found are the fat bodies, burning of lipids gives us energy.
Answer:
A.
Explanation:
The correct sequencing of DNA nucleotides to match A, T, T, G, C is T, A, A, C, G because the nucleotide matches are: Adenine-Thymine, and Guanine-Cytosine. This works both ways, A-T or T-A, and G-C or C-G. The correct sequence therefore is A.
Answer: <u>Unwind
</u>
Explanation: Transcription is a process where a DNA strand is used to make a copy of mRNA. A complementary mRNA strand is made from the DNA strand. This mRNA is then later used to make proteins. In this process the junk information, present in DNA in form of introns is also spliced.
DNA is a double stranded structure, which is present in helical structure and both the strands are twisted together. In order to make the mRNA copy with the help of the enzyme RNA polymerase, DNA must open up. Then only RNA polymerase will be able to access the nucleotides of DNA.
Arthritis
Arthritis is a joint disorder in
which there is inflammation of one or more joints. Arthritis is frequently accompanied by joint
pain. There are many types of arthritis and over 100 have been identified. The causes
of arthritis include injury, metabolic abnormalities, hereditary factors,
effect of infections, and a misdirected immune system. Arthritis is mostly
common among women and occurs as people get older. Severe arthritis can result
in chronic pain, inability to do daily activities and can cause difficulty in walking.
Answer: 48.93 mL of sprite
Volume of blood in 7 Kg human = 5 L
Percentage of plasma in blood = 55%
Volume of plasma in 5 L blood = (1 L = 10 dL)
Concentration of glucose in plasma = 80 mg/dL
Amount of glucose present in 27.5 dL : 80 mg /dL × 27.5 dL= 2200 mg
Let the volume of sprite with 2200 mg glucose be x
Concentration of glucose in sprite = 44.96 mg/mL
Explanation:
