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balandron [24]
3 years ago
13

Find the exact value expression. tan^-1 (0)

Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0

Answer:

Hence, the exact value of the expression is:

0

Step-by-step explanation:

We are given a expression as:

tan^-1 (0).

We have to find the value of a angle such that it is obtained on taking inverse of tangent of 0.

Let us consider,

Θ=tan^-1(0)

on taking tangent function on both side of the equation we get:

tan(θ)=tan(tan^-1(0))

tan(θ)=0

tan(θ)=tan(0)

since,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

Hence,

\tan(0)=\dfrac{\sin 0}{\cos 0}\\\\\tan 0=\dfrac{0}{1}\\\\\tan 0=0

Hence we get:

Θ=0.

Hence, the exact value of the expression is:

0

Nezavi [6.7K]3 years ago
3 0
Zero. The negative one means arctan. Arctan times 0 is 0. 
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3 years ago
I need help understanding square roots
Vlad [161]

I wonder if you mean to write \sqrt[3]{256} in place of 3\sqrt{256}...

If you meant what you wrote, then we have

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If you meant to write \sqrt[3]{256} (the cube root of 256), then we could go on to have

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3 years ago
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wariber [46]

Answer:

6

Step-by-step explanation:

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Using the Pythagorean theorem, which is a^2 + b^2 = c^2, we have (3√2)^2 + (3√2)^2 = c^2.

Note: c is the hypotenuse of the triangle.

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3 years ago
A robot at a carnival booth randomly tosses a dart at a square target with 8 inch sides and a circle with a 3 inch radius in the
VikaD [51]

Step-by-step explanation:

hope u will get help with the attachment

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3 years ago
Help with a few questions pleaseeeeee
mel-nik [20]
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i think this is all right you might want to check my work!
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